1.2Consider a 2.00 mol sample of perfect gas initially at p = 112 kPa and T = 278 K. The temperature ofperfect gas with constant volume heat capacity 3R/2 is reduced by 28 K. Calculate1.2.1 the final pressure. Use 4 significant figures.1.2.2 the change in internal energy. Use 5 significant figures.1.2.3 the heat transferred in the process. Use 5 significant figures.1.2.4 the work done.

Answered: Image /qna-images/answer/64c763b0-371c-4e6a-9018-7c676af1cee5.jpg

Answered: 1.2 Consider a 2.00 mol sample of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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How do I calculate, Table 4.
Esc M Inbox (2,372) - ftantill@ude X app.101edu.co ← → C < STARTING AMOUNT 56°F JRain off and on X 22F-CHEM 103-510: Generax 4 F2 4 F3 ▬ Aktiv Chemistry -572 mol H₂ What is the change in enthalpy when 1.25 moles of O₂ are reacted with an excess H₂ of according to the following balanced chemical reaction: H₂O(l) ADD FACTOR O Search F4 458 g 0₂ DII FS 1 KJ Convert 33 psi to kpa | Quic X 2 Question 7 of 41 H₂(g) + O:(g) → 2 - ΔΗ= 572| kJ 715 CL 2 g H₂O F6 1.25 ANSWER * 18.02 CHEM103- Lecture Notes - -458 F7 mol O₂ mol H₂O 2.02 0 PrtScn FB RESET 2 -715 J N X Home F9 32.0 Enthalpy of Formation Rear X g H₂ hule End F10 PgUp F11 + 30 6 POD PgDn F12 0 Update X Submit 6:56 PM 12/6/2022 D 7te per Jun
6.2 The standard enthalpy of formation of NH3 (g) at 298 K is equal to -462.11 kJ mol'. Using the heat capacity data given below (valid for the temperature range of 298 K to 1600 K). Cp.m" (H₂) / J. K¹ mol¹ = 29.07-0.837 x 10³ +2.012 x 106 Cp.m" (N₂) / J. K¹ mol¹ = 26.98 +5.192 x 10³ -0.3376 x 106 Cp. m (NH3)/J.K¹ mol = 25.89 +32.58 x 103-3.046 x 10 Calculate the standard molar heat of formation of NH3 (g) at 900 K (in kJ.mol'), at 1000 K. Give your final answer to 3 significant figures.
Calculate the change of enthalpy for the reaction 2AI (s) + 3C12 (g) --> 2AICI3 (s) from the following reactions: Reaction 1: 2AI (s) + 6HCI (aq) --> 2AICI3 (aq) + 3H2 (g) Change in enthalpy: -1049 kJ Reaction 2: HCI (g) --> HCI (aq) Change in enthalpy: -74.8 kJ/mol Reaction 3: H2 (g) + Cl2 (g) --> 2HCI (g) Change in enthalpy: -1845. kļ/mol Reaction 4: AICI3 (s) --> AICI3 (aq) Change in enthalpy: -323. kJ/mol Include the following: • The numerical answer with correct units. • State which reactions, if any, you had to "Flip". • State which reactions you had to multiply, if any, to get the correct amount of the compound.
I need to find Q in joules (J) for both experiment #1 and #2 but I'm unsure of how to write the equation they gave me
V:OY IA %YA N& 令 l PNG.9 → حداد H.W) calculate AçH° (500 K) for methane by using the data given on the temperature dependence of heat capacities. CH4(g)+2O2(g)→CO2(g)+2H2O(g) AÇH° (298 K) -891 kJ Cp,m(CO2) = 44.22 + 8.79 × 10-37 - 8.62 × 105 T2 Cp.m(H2O) = 75.29 + 0 + 0 Cp,m(O2) = 29.96 + 4.18 × 10-37 1.67 × 105 T2 Cp,m(CH4) = 35.31
A quantitity of 100mL of 0.500 MHCl was mixed with 50 mL of 0.500M NaOH in a constant pressure calorimeter of negligible heat capacity. The initial temperature of the HCl and NaOH solutions was the same, 20ºC, and the final temperature of the mixed solution was 22.3ºC. Calculate the heat change for neutralization reaction on a molar baisis.
3. 4 6. 7. 10 There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide: CaC(s) + 2 H,O(g) → C,H;(g) + Ca(OH),(s) AH=-414. kJ In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6C,H2(9) + 3 CO,(9) + 4 H,O(9) - 5 CH,CHCO,H(9) AH = 132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. Round your answer to the nearest kJ. nue
1.00 mole of an ideal diatomic gas (for which Cv 5R/2) is in a rigid container with a constant volume of 2.00 L. The gas is heated from 250.0 K to 300.0 K. Calculate the AS(gas) for this process, in J/K. J/K 1 4 C 7 8 +/- x 10 3. co 2. 5,
< 6:43 What is the change in enthalpy when 1.50 moles of H₂ are reacted with an excess O₂ of according to the following balanced chemical reaction: ADD FACTOR x( ) 2 STARTING AMOUNT Question 5 of 25 2.02 H₂(g) + O₂(g) → 2 ΔΗ = -572 -381 -429 381 32.0 -572 429 " 1.50 1 2 18.02 X kJ mol H₂ KkJ ANSWER g 0₂ g H₂O mol O₂ J mol H₂O g H₂ Tap here or pull up for additional resources Submit H₂O (1) RESET 3

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