We asked UST employees to tell us how many megabytes of memory (RAM) they have on their computer. We would like to test to see if the mean amount of memory is the same for three different academic departments. We have the memory amounts for six faculty members' machines in the three departments shown below. Dept. 1 Dept. 2 Dept. 3 1 2048 4096 4096 2 1024 2048 4096 3 1024 2048 8192 computer 4 2048 4096 8192 5 1024 2048 4096 6 2048 8192 2048 Here is the ANOVA table: Source DF Adj SS Adj MS F-Value P-Value Factor x 39263346 19631673 x.xx 0.025 Error xx 61691221 4112748 Total xx 100954567 After ANOVA, assume that we want to do all of the pairwise comparisons between the means and construct confidence interval estimates for the size of the difference between means. Tukey Pairwise Comparisons: Grouping Information Using the Tukey Method and 95% Confidence Factor N Mean Grouping dept 3 6 5120 A dept 2 6 3755 A B dept 1 6 1536 B Means that do not share a letter are significantly different. Construct a 95% confidence interval estimate for the difference between the mean for department 1 and the mean for department 2. Start by subtracting x bar 1 from x bar 2 to get a positive difference. You may use a t* multiplier of 2.13. Choose the interval here that matches most closely the interval you constructed. Answers: 1. 1990 to 5519 2. -820 to 5257 3. 546 to 6622 4. -1673 to 4404
We asked UST employees to tell us how many megabytes of memory (RAM) they have on their computer. We would like to test to see if the
Dept. 1 Dept. 2 Dept. 3
1 2048 4096 4096
2 1024 2048 4096
3 1024 2048 8192
computer 4 2048 4096 8192
5 1024 2048 4096
6 2048 8192 2048
Here is the ANOVA table:
Source |
DF |
Adj SS |
Adj MS |
F-Value |
P-Value |
Factor |
x |
39263346 |
19631673 |
x.xx |
0.025 |
Error |
xx |
61691221 |
4112748 |
|
|
Total |
xx |
100954567 |
|
After ANOVA, assume that we want to do all of the pairwise comparisons between the means and construct confidence interval estimates for the size of the difference between means.
Tukey Pairwise Comparisons: Grouping Information Using the Tukey Method and 95% Confidence
Factor |
N |
Mean |
Grouping |
|
dept 3 |
6 |
5120 |
A |
|
dept 2 |
6 |
3755 |
A |
B |
dept 1 |
6 |
1536 |
|
B |
Means that do not share a letter are significantly different.
Construct a 95% confidence
Answers:
1. 1990 to 5519
2. -820 to 5257
3. 546 to 6622
4. -1673 to 4404
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