A researcher aims to determine the average time it takes for a specific species of bacteria to divide. By observing 21 cells under a microscope, she records the following division times in hours:8.8, 7, 9.8, 8.4, 7.8, 8, 9.6, 7, 8.2, 8, 8.6, 8.6, 8.7, 7.3, 8.6, 7.3, 8.3, 8.6, 8.9, 7.6, 7.9Given that the population standard deviation is \( \sigma = 0.6 \), she constructs a 99% confidence interval for the average time it takes this species of bacteria to divide.Required calculations include:- \( \bar{x} \) (Sample Mean):- \( \frac{\alpha}{2} \) (Significance Level):- \( z_{\frac{\alpha}{2}} \) (Z-Score for Confidence Level):- Margin of Error \( E \):The conclusion states: "We are 99% confident that this species of bacteria takes, on average, between [lower bound] and [upper bound] hours to divide."Details regarding the calculations and further explanations are accessible for educational purposes on the website.

Given data,n=21σ=0.6CI=0.99α=1-0.99=0.01

Answered: A researcher wants to know how long it…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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