We asked UST employees to tell us how many megabytes of memory (RAM) they have on their computer. We would like to test to see if the mean amount of memory is the same for three different academic departments. We have the memory amounts for six faculty members' machines in the three departments shown below. Dept. 1 Dept. 2 Dept. 3 1 2048 4096 4096 2 1024 2048 4096 3 1024 2048 8192 computer 4 2048 4096 8192 5 1024 2048 4096 6 2048 8192 2048 Here is the ANOVA table: Source DF Adj SS Adj MS F-Value P-Value Factor x 39263346 19631673 x.xx 0.025 Error xx 61691221 4112748 Total xx 100954567 After ANOVA, assume that we want to do all of the pairwise comparisons between the means in this case. Tukey Pairwise Comparisons: Grouping Information Using the Tukey Method and 95% Confidence Factor N Mean Grouping dept 3 6 5120 A dept 2 6 3755 A B dept 1 6 1536 B Means that do not share a letter are significantly different. Using the Tukey Table above, describe what you learned about the pairwise comparisons between means. Answers: 1. mean dept 1 not = mean dept 3 2. mean dept 2 not = mean dept 3 3. all means are different 4. mean dept 1 not = mean dept 2
We asked UST employees to tell us how many megabytes of memory (RAM) they have on their computer. We would like to test to see if the
Dept. 1 Dept. 2 Dept. 3
1 2048 4096 4096
2 1024 2048 4096
3 1024 2048 8192
computer 4 2048 4096 8192
5 1024 2048 4096
6 2048 8192 2048
Here is the ANOVA table:
Source |
DF |
Adj SS |
Adj MS |
F-Value |
P-Value |
Factor |
x |
39263346 |
19631673 |
x.xx |
0.025 |
Error |
xx |
61691221 |
4112748 |
|
|
Total |
xx |
100954567 |
|
After ANOVA, assume that we want to do all of the pairwise comparisons between the means in this case.
Tukey Pairwise Comparisons: Grouping Information Using the Tukey Method and 95% Confidence
Factor |
N |
Mean |
Grouping |
|
dept 3 |
6 |
5120 |
A |
|
dept 2 |
6 |
3755 |
A |
B |
dept 1 |
6 |
1536 |
|
B |
Means that do not share a letter are significantly different.
Using the Tukey Table above, describe what you learned about the pairwise comparisons between means.
Answers:
1. mean dept 1 not = mean dept 3
2. mean dept 2 not = mean dept 3
3. all means are different
4. mean dept 1 not = mean dept 2
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