**Title: Constructing an 89% Confidence Interval for Coronary Artery Bypass Surgery Time**A surgeon seeks to determine the average time to complete a coronary artery bypass surgery. She collects data from 24 surgeries, measuring the time in hours as follows:4.8, 4.7, 4.5, 4.8, 5.1, 4.8, 4.5, 4.8, 4.2, 4.9, 4.7, 4.9, 4.6, 4.6, 4.5, 4.9, 4.8, 4.5, 4.9, 4.8, 5.1, 4.7, 4.7, 4.6Given a population standard deviation (σ) of 0.25, the task is to construct an 89% confidence interval for the average surgery time.**Calculations Needed:**1. **Sample Mean (x̄):** Calculate the mean of the sample data points.2. **Confidence Level (α/2):** Determine the significance level associated with the 89% confidence interval.3. **Z-value (zᵦ/₂):** Find the Z-score corresponding to the confidence level.4. **Margin of Error (E):** Use the formula for the margin of error, E = zᵦ/₂ * (σ/√n), where n is the sample size.5. **Confidence Interval:** Calculate the range using (x̄ - E) to (x̄ + E).**Conclusion:**We are 89% confident that the mean time needed to complete a coronary artery bypass surgery is between [lower limit] hours and [upper limit] hours.**Additional Resources:**For further clarification or assistance, please refer to this [forum link].(Note: The placeholders for calculations should be filled in with the appropriate computations based on the data provided.)

Answered: A surgeon would like to know how long…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(0.5,3.4),(0.2,3.7),(1.2,5.5),(2.9,7.3),(3.4,7.9),(2.4,5.9),(4.4,8.1),(4.5,7.9),(4.9,7.9),(3.3,6.6) Compute the coefficients of polynomials of degrees 3,4,5,6,7,8,9(3 to 9) that approximates the above data points in the least-square sense using Cholesky factorization.
How would you conduct a sample of people in your community so that you could see which flavors are most popular? Give specific details of how you would collect your data, and state how many responses would be sufficient.
The table shows the leading causes of death in a certain country in a recent year. The population of the country was 311311 million. If you lived in a typical city of 500,000, how many people would you expect to die of cancercancer each year? Cause Deaths Cause Deaths Heart disease 596 comma 700596,700 Alzheimer's disease 84 comma 90084,900 Cancer 575 comma 300575,300 Diabetes 73 comma 40073,400 Chronic respiratory diseases 143 comma 100143,100 Pneumonia/Influenza 53 comma 40053,400 Stroke 128 comma 600128,600 Kidney disease 45 comma 30045,300 Accidents 122 comma 500122,500 Suicide 38 comma 60038,600 About people would be expected to die of cancer each year. (Type a whole number. Round to the nearest person as needed.)
The table below shows the share of income going to each quintile of the income distribution for Neverland in 1980 and 1990. Complete the table below finding the the cumulative share of income for 1980 and 1990 and answer the following: Share of income in Cumulative share of Share of income in Cumulative share of Quintiles 1980 income in 1980 1990 income in 1990 1st 7% 6.6.% 2nd 11.5% 11.5% 3rd 17% 16.3% 4th 24.8% 22.7% 5th 39.7% 42.9% a) Sketch the Perfect Equality line and the Lorenz curve for 1980 and for 1990. Don't forget to label your graph and your curves! b) According to the Lorenz curves that you draw in (a), which year had worse income inequality, 1980 or 1990? JUSTIFY your answer! NOTE: This is a file upload question. Work your answer in a piece of paper, take a picture and upload your file.
Rate 528 715 366 391 815 527 441 976 588 278 559 686 604 498 947 1026 515 474 728 796 493 526 919 1122 304 519 559 453 438 236 176 454 661 361 226 478 381 698 351 157 347 428 554 332 610 279 237 796 365 998 618 523 491 380 804 758 1153 674 731 553 422 552 645 506 480 843 683 682 581 601 493 372 613 836 390 1053 816 936 152 444 695 597 430 920 607 996 452 506 376 282
Rate 528 715 366 391 815 527 441 976 588 278 559 686 604 498 947 1026 515 474 728 796 493 526 919 1122 304 519 559 453 438 236 176 454 661 361 226 478 381 698 351 157 347 428 554 332 610 279 237 796 365 998 618 523 491 380 804 758 1153 674 731 553 422 552 645 506 480 843 683 682 581 601 493 372 613 836 390 1053 816 936 152 444 695 597 430 920 607 996 452 506 376 282
If 30 participants each completed a memory task three times — once each after having no, moderate, or high levels of caffeine, calculate the total degrees of freedom.
A researcher wants to know how long it takes, on average, for a certain species of bacteria to divide. She watches 17 cells through a microscope and times how long it takes them to divide. She obtains the following data, in hours:6.7, 10.5, 4.8, 5.2, 5.2, 10.6, 4.4, 5.7, 10.9, 7.5, 5.3, 4.4, 5.7, 5.2, 6.9, 4.5, 7.7Assuming the population standard deviation is σ=2σ=2, construct a 94% confidence interval for the average time it takes this species of bacteria to divide.xˉ=x̄=α2=α2=zα2=zα2=Margin of Error: E=E=We are 94% confident that this species of bacteria takes, on average, between hours and hours to divide.___
solve for UCLp
Rate 528 715 366 391 815 527 441 976 588 278 559 686 604 498 947 1026 515 474 728 796 493 526 919 1122 304 519 559 453 438 236 176 454 661 361 226 478 381 698 351 157 347 428 554 332 610 279 237 796 365 998 618 523 491 380 804 758 1153 674 731 553 422 552 645 506 480 843 683 682 581 601 493 372 613 836 390 1053 816 936 152 444 695 597 430 920 607 996 452 506 376 282

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