We asked UST employees to tell us how many megabytes of memory (F have on their computer. We would like to test to see if the mean amou is the same for three different academic departments. We have the me amounts for six faculty members' machines in the three departments sH Dept. 1 Dept. 2 Dept. 3 1 4096 4096 4096 2 4096 2048 4096 3 4096 2048 8192

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We asked UST employees to tell us how many megabytes of memory (RAM) they
have on their computer. We would like to test to see if the mean amount of memory
is the same for three different academic departments. We have the memory
amounts for six faculty members' machines in the three departments shown below.
Dept. 1 Dept. 2 Dept. 3
1
4096
4096 4096
4096
2048 4096
3.
4096
2048 8192
computer 4
8192
4096
8192
4096
2048
4096
6.
2048
8192
2048
Choose the best null and alternative hypothesis statement from these choices:
Null hypothesis: all the means are different. Alternative: mean for dept 1 = mean for dept 2
= mean for dept 3
O Null: mean for dept 1 = mean for dept 2 = mean for dept 3 and Alternative: at least one
mean is different
O Null hypothesis: mean for dept 1 = mean for dept 2 Alternative: mean for dept 2 = mean for
dept 3
%3D
O Null hypothesis: mean for dept 1 = mean for dept 2 = mean for dept 3 Alternative: all the
%3D
means are different
Transcribed Image Text:We asked UST employees to tell us how many megabytes of memory (RAM) they have on their computer. We would like to test to see if the mean amount of memory is the same for three different academic departments. We have the memory amounts for six faculty members' machines in the three departments shown below. Dept. 1 Dept. 2 Dept. 3 1 4096 4096 4096 4096 2048 4096 3. 4096 2048 8192 computer 4 8192 4096 8192 4096 2048 4096 6. 2048 8192 2048 Choose the best null and alternative hypothesis statement from these choices: Null hypothesis: all the means are different. Alternative: mean for dept 1 = mean for dept 2 = mean for dept 3 O Null: mean for dept 1 = mean for dept 2 = mean for dept 3 and Alternative: at least one mean is different O Null hypothesis: mean for dept 1 = mean for dept 2 Alternative: mean for dept 2 = mean for dept 3 %3D O Null hypothesis: mean for dept 1 = mean for dept 2 = mean for dept 3 Alternative: all the %3D means are different
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