A researcher wants to know how long it takes, on average, for a certain species of bacteria to divide. Shewatches 16 cells through a microscope and times how long it takes them to divide. She obtains thefollowing data, in hours:8, 6.6, 9, 7.4, 6.1, 8.9, 10, 8.1, 8.4, 8.3, 8.3, 8.4, 4.9, 7.8, 7.4, 6.3Assuming the population standard deviation is o =average time it takes this species of bacteria to divide.1.1, construct a 97% confidence interval for theMargin of Error: EWe are 97% confident that this species of bacteria takes, on average,betweenhours andhours to divide.

Given data,8,6.6,9,7.4,6.1,8.9,10,8.1,8.4,8.3,8.3,8.4,4.9,7.8,7.4,6.3Population standard deviation…

Answered: A researcher wants to know how long it…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A certain species of tree has an average life span of 130 years. A researcher has noticed a large number of trees of this species washing up along a beach as driftwood. She takes core samples from 27 of those trees to count the number of rings and measure the widths of the rings. Counting the rings allows the researcher to determine the age of each tree. Her data are displayed in the provided table. 98 79 147 200 130 60 51 127 105 75 120 113 200 190 81 98 160 165 134 62 152 66 68 124 190 159 60 One of her interests is determining if this sample provides evidence that the average age of the driftwood is less than the 130 year life span expected for this type of tree. If the average age is less than 130 years it might suggest that the trees have died from unusual causes, such as invasive beetles or logging. Use technology to create a randomization distribution with at least 1,000 values…
The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15% pike. Five years later it sampled the lake to see if the distribution of fish had changed. It found that the 500 fish in the sample were distributed as follows. Catfish Bass Bluegill Pike 122 75 222 81 In the 5-year interval, did the distribution of fish change at the 0.05 level Find the value of the chi-square statistic for the sample. Estimate the P-value of the sample test statistic. P-value > 0.100 0.050 < P-value < 0.100 0.025 < P-value < 0.050 0.010 < P-value < 0.025 0.005 < P-value < 0.010 P-value < 0.005 Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories? Since the P-value > α, we fail to reject the null hypothesis. Since the P-value > α, we reject the null hypothesis. Since the…
rofessor Cornish studied rainfall cycles and sunspot cycles. (Reference: Australian Journal of Physics, Vol. 7, pp. 334-346.) Part of the data include amount of rain (in mm) for 6-day intervals. The following data give rain amounts for consecutive 6-day intervals at Adelaide, South Australia. 7 28 7 1 69 3 1 4 22 7 16 4 54 160 60 73 27 3 3 1 7 144 107 4 91 44 1 8 4 22 4 59 116 52 4 155 42 24 11 43 3 24 19 74 26 63 110 39 34 71 52 39 8 0 15 2 14 9 1 2 4 9 6 10 (i) Find the median. (Use 1 decimal place.)(ii) Convert this sequence of numbers to a sequence of symbols A and B, where A indicates a value above the median and B a value below the median. Test the sequence for randomness about the median at the 5% level of significance. (b) Find the number of runs R, n1, and n2. Let n1 = number of values above the median and n2 = number of values below the median. R n1 n2 (c) In the case, n1 > 20, we cannot use Table 10 of Appendix II to find the critical…
Consider the following table: SS DF MS FL Among Treatments 4468.45 Error Total ? 10 706.87 15 Step 1 of 8: Calculate the sum of squares of experimental error. Please round your answer to two decimal places.
5 and 6. The following data was collected from 1 bag of Hershey Kisses®. Each Kiss® was weighed in grams with the wrapper and recorded in the table below. Hershey claims that there are 368 grams of chocolate in one bag. Hershey Kiss Weights in Grams 4.76 4.72 4.74 4.55 4.91 4.74 4.78 4.71 4.80 4.78 4.78 4.75 4.79 4.82 4.91 4.83 4.68 4.74 4.70 4.80 4.70 4.76 4.70 4.83 4.93 4.74 4.84 4.82 4.76 4.77 4.72 4.78 4.83 4.75 4.74 4.68 4.84 4.71 4.71 4.76 4.66 4.78 4.73 4.74 4.92 4.77 4.80 4.79 4.86 4.64 4.78 4.70 4.75 4.78 4.76 4.83 4.66 4.77 4.83 4.78 4.69 4.81 4.68 4.78 4.88 4.72 4.85 4.85 4.81 4.74 4.80 4.82 4.84 4.70 4.85 4.70 4.81 4.72 4.79 4.73 4.61 Based on Hershey's® claim for 368 total net grams of chocolate in the bag, approximately how many Kisses® too many or too few are there? Assume that the Kisses® were weighed with the wrapper, each wrapper weighs 0.12 grams, and the net grams listed on the bag are for the chocolate only. Give some possible…
A researcher was studying how much electricity (in kilowatt hours) people in Spain and Germany used in their homes last year. The researcher took a random sample of people from each country to test if the average electricity usage was significantly different. Here is a summary of their results: Electricity usage Country Mean StDev SE mean Spain 100 1780 415 41.5 Germany 100 1690 405 40.5 95% CI for us - PG: 90 + 114.4 The researcher wants to use these results to test Ho: µs = PG versus H: µs # pG. Assume that all conditions for inference have been met. Based on the interval, what do we know about the corresponding P-value and conclusion at the a = 0.05 level of significance? The P-value is less than a=0.05, and they should conclude that there is a difference between the means. The P-value is less than a=0.05, and they cannot conclude that there is a difference between the means. The P-value is greater than a=0.05, and they cannot conclude that there is a difference between the means.…
Listed below are pulse rates (beats per minute) from samples of adult males and females. Does there appear to be a difference? Find the coefficient of variation for each of the two samples; then compare the variation. Male 8787 7171 6363 7070 7272 5050 6464 5656 8484 7171 6262 6262 9797 5555 6262 Female 6868 8181 8282 6969 7676 8484 8787 8888 8787 9090 9191 6868 8686 8181 7878 The coefficient of variation for the male pulse rates is nothing%.
If there is no seasonal effects on human births, we would expect equal numbers of children to be born in each season (winter, spring, summer, and fall). A student takes a census of her statistics class and finds that of the 120 students in the class, 25 were born in winter, 35 in spring, 32 in summer, and 28 in fall. She wonders if the excess in the spring is an indication that births are not uniform throughout the year. What is the chi-square statistic? What is the p-value? ( 3 decimal places) What is your decision? What is your conclusion in context?
A researcher wants to know how long it takes, on average, for a certain species of bacteria to divide. She watches 15 cells through a microscope and times how long it takes them to divide. She obtains the following data, in hours: 6.3, 7.1, 8.7, 6.1, 7.4, 7.5, 6.4, 7.8, 7.5, 4.4, 6.1, 7.1, 5.9, 5.9, 7.6 Construct a 95% confidence interval for the average time it takes this species of bacteria to divide. S = %D Margine of Error: E = We are 95% confident that this species of bacteria takes, on average, between hours to divide. hours and
A researcher wants to know how long it takes, on average, for a certain species of bacteria to divide. She watches 17 cells through a microscope and times how long it takes them to divide. She obtains the following data, in hours:6.7, 10.5, 4.8, 5.2, 5.2, 10.6, 4.4, 5.7, 10.9, 7.5, 5.3, 4.4, 5.7, 5.2, 6.9, 4.5, 7.7Assuming the population standard deviation is σ=2σ=2, construct a 94% confidence interval for the average time it takes this species of bacteria to divide.xˉ=x̄=α2=α2=zα2=zα2=Margin of Error: E=E=We are 94% confident that this species of bacteria takes, on average, between hours and hours to divide.___
Can you please help in part d and e? I'm also attaching an example of that question.

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