rofessor Cornish studied rainfall cycles and sunspot cycles. (Reference: Australian Journal of Physics, Vol. 7, pp. 334-346.) Part of the data include amount of rain (in mm) for 6-day intervals. The following data give rain amounts for consecutive 6-day intervals at Adelaide, South Australia. 7 28 7 1 69 3 1 4 22 7 16 4 54 160 60 73 27 3 3 1 7 144 107 4 91 44 1 8 4 22 4 59 116 52 4 155 42 24 11 43 3 24 19 74 26 63 110 39 34 71 52 39 8 0 15 2 14 9 1 2 4 9 6 10

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rofessor Cornish studied rainfall cycles and sunspot cycles. (Reference: Australian Journal of Physics, Vol. 7, pp. 334-346.) Part of the data include amount of rain (in mm) for 6-day intervals. The following data give rain amounts for consecutive 6-day intervals at Adelaide, South Australia.

7 28 7 1 69 3 1 4 22 7 16 4 54 160
60 73 27 3 3 1 7 144 107 4 91 44 1 8
4 22 4 59 116 52 4 155 42 24 11 43 3 24
19 74 26 63 110 39 34 71 52 39 8 0 15 2
14 9 1 2 4 9 6 10

(i) Find the median. (Use 1 decimal place.)

(ii) Convert this sequence of numbers to a sequence of symbols A and B, where A indicates a value above the median and B a value below the median. Test the sequence for randomness about the median at the 5% level of significance.

(b) Find the number of runs Rn1, and n2. Let n1 = number of values above the median and n2 = number of values below the median.

R  
n1  
n2  


(c) In the case, n1 > 20, we cannot use Table 10 of Appendix II to find the critical values. Whenever either n1 or n2 exceeds 20, the number of runs R has a distribution that is approximately normal, as follows.

 

We convert the number of runs R to a z value, and then use the normal distribution to find the critical values. Convert the sample test statistic R to z using the following formula. (Use 2 decimal places.)

z =
R – μR
σR


(d) The critical values of a normal distribution for a two-tailed test with level of significance α = 0.05 are -1.96 and 1.96 (see Table 5(c) of Appendix II). Reject H0 if the sample test statistic z ≤ -1.96 or if the sample test statistic z ≥ 1.96. Otherwise, do not reject H0.

Sample z ≤ -1.96 -1.96 < sample z < 1.96 Sample z ≥ 1.96
Reject H0 Fail to reject H0 Reject H0
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