Usually found in prokaryotes, regulatory sequences lying adjacent to the DNA being transcribed are composed of a promoter located next to a(n) that interacts and is controlled by regulatory protein. A rho binding domain в) ТАТА box C operator D RNA polymerase holoenzyme
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![Usually found in prokaryotes, regulatory sequences lying adjacent to the DNA being transcribed are composed of a promoter located
next to a(n)_ that interacts and is controlled by regulatory protein.
(A rho binding domain
(в) ТАТА box
c) operator
D RNA polymerase holoenzyme](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f67e71a-ca9f-41cd-807f-824631188f97%2F89e1046c-988b-420b-bb3e-07524b0769c6%2Fhoa5ha6_processed.png&w=3840&q=75)
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- Briefly explain WHY a 5 7-methylguanosine cap is only added to mRNA, not to tRNA orrRNA. (Please note that I am not looking for the function of the 5’ cap, but for the mechanismrestricting capping to messenger RNA.)TRUE FALSE EF-Ts factor regenerates EF-Tu/GDP from EF-Tu/GTP for the next round of elongation cycle in prokaryotic translation. The sigma o subunit of RNA polymerase is replaced by NusA to recognise the promoter region of a gene. The -10 and -35 sequences in E. coli DNA are referred to as untranslated region. In human, translation begins before transcription of an mRNA completes. The distal histidine stabilises the iron in heme group of a deoxyhaemoglobin. Receptor for epinephrine consists of seven transmembrane helices. Membrane receptors bind to hydrophobic signaling molecules. Amino acids, glucose and fatty acids are taken up by transporters into liver cells. Glycerol and fatty acids are synthesized from the intermediates of glycolysis. Synthesis of fatty acid occurs in cytoplasm. Triacylglycerol can be obtained from diet and also synthesized in liver cells. Ammonia and keto acid are formed in transamination.Usually found in prokaryotes, regulatory sequences lying adjacent to the DNA being transcribed are composed of a promoter located next to a(n) ____ that interacts and is controlled by regulatory protein. TATA box rho binding domain RNA polymerase holoenzyme operator
- EF-Ts factor regenerates EF-Tu/GDP from EF-Tu/GTP for the next round of elongation cycle in prokaryotic translation. The sigma subunit of RNA polymerase is replaced by NusA to recognise the promoter region of a gene. The -10 and -35 sequences in E. coli DNA are referred to as untranslated region. In human, translation begins before transcription of an mRNA completes. this statement true or false.6) The C-terminal domain (CTD) of yeast RNA polymerase II (RPB) subunit RPB1 contains the repeating amino acid sequence "-PTSPSYS-". Explain how this sequence plays a role in the regulation of the transcriptional activity of the yeast RPB holoenzyme.During translation, the tRNA antlicodon sequence G-A-U vyould blnd to which MRNA codon (plck one of the cholces I -V below)? Note: all of the sequencos for tho quostlon and answors use the standard convention for representing ollgonuclootidos discussed In class whoro tho 5'-ond Is at the loft and the 3'-ond Is at the right. I) G-A-U II) U-A-G I) C-U-A IV) A-U-C V A-T-C OA. none of the cholces OB. IV Oc." OD.! OE, II
- identify start/end site, which amino acid will be on the tRNA that is the first to bind to the A site of ribosome, anticodon on the tRNA in the P site of the ribosome when release factor bings to A site, and what amino acid sequence of the protein that will be formed from mRNA? Here is the mRNA sequence:5'GUUUCCCGUAUACAUGCGUGCCGGGGGCCCGUUACCAGGCCUCAUUAUUGGAUAACGGAAAAAAAAAAAAA3'Referring to the genetic code presented in Figure , give the aminoacids specified by the following bacterial mRNA sequences. Q. 5′ –AUGUUUAAAUUUAAAUUUUGA–3′19Eukaryotic messenger RNA and hnRNA both have poly (A) tails at their 3'-ends. Yesorno 20Messenger RNA splicing and export are uncoupled processes. Yesorno twenty oneWhich of the following plays an important role in directing newly synthesized proteins to specific cellular destinations?A.signal sequenceb.nuclear localization signalc.chain elongation stretchD.Shine – Dalgarno
- IF-2, IF-3, EF-Tu, EF-G and RF-1 are all involved in prokaryotic translation. List the roles of each factor in the process of translation--please be sure to note if the factor binds GTP. (You can list the factors with the function listed next to the factor.)Given the following genomic sequence which contains 2 exons and CDNA sequence predidt the amino acid sequence of the exons which are part of the coding region of a protein. How many nucleotides make up the intron? Second letter UAU TV UACJ UAA Stop|UGA Stop A UAG Stop UG Trp UUU1 Phe UUCJ UGU1, UGCJ UCU) Cys UCC Ser UCA ULA UCG CUUT CUC CUA CUG CCU CAUT C4C His CAAT CAGJ OGU CCC Leu CA CGC FArg CGA Gln CGG Pro CCG AUU AUC lle AUA ACU AGU AAU AACJ AAA 1 AAGYS Asn Ser ACC Thr ACA AGC. AGA Arg AUG Mer ACG, AGG GCU GAUT GACJ GGU GGC GUU Asp GUC Val GUA Gly Ala GAA Glu GAGJ GGA GGG GUG GCG G. Genomic antisense sequence: 5'-TAACTGATTCTAGGCTACTCTTTCACCTAA-3" CDNA sequence: 5'-TAACTGATTTCTTTCACCTAA-3" I Use the editor to format your answer First letter 皇 Third letterc) A gene in a bacteria has the following DNA sequences (the promoter sequence is positioned to the left but is not shown): 5'-CAATCATGGAATGCCATGCTTCATATGAATAGTTGACAT-3' 3'-GTTAGTACCT TACGGTACGAAGTATACTTATCAACTGTA-5' i) By referring to the codon table below, write the corresponding mRNA transcript and polypeptide translated from this DNA strand. 2 Second letter с A UUUPhe UAU Tyr UAC. UGU UGCJ UCU) UCC UCA UUG Leu UCG Cys UUC UUA Ser UAA Stop UGA Stop A UAG Stop UGG Trp G CUU CÚC CCU ССС CAU CGU His САC Pro CC CỦA Leu ССА CAA Arg CGA CUG J CCG) CAG Gin CGG AUU ACU AAU Asn AGU Ser AUC le АСC АCА AAC AAA AGC. Thr JArg AUA AGA AUG Met ACG AAG Lys AGG. GAU Asp GUU) GCU GCC GCA GCG GGU" GGC GGA GGG GUC Val GUA GAC Ala Gly GAA Glu GAGJ GUG ii) If the nucleotide indicated by the highlighted bold letter undergoes a mutation that resulted in deletion of the C:G base pair, what will be the resulting amino acid sequence following transcription and translation? Third letter DUAG DUAG DUAG A. First…
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