Use standard free energy data from the table below to calculate the standard free energy change for the reaction below at (298 K). TiCl4(g) + 2H2O(g) → TiO2 (s) + 4HCl(g) • Your answer should include three significant figures. Substance AG mol KJ ΔΗ kJ mol J S298 mol K TiCl4(g) -737.2 -802.1 252.3 TiO2(s) -889.1 -944.7 50.2 Provide your answer below: kJ/mol H₂O(g) -228.57 -241.82 188.71 HCl(g) -95.4 -92.5 186.6
Use standard free energy data from the table below to calculate the standard free energy change for the reaction below at (298 K). TiCl4(g) + 2H2O(g) → TiO2 (s) + 4HCl(g) • Your answer should include three significant figures. Substance AG mol KJ ΔΗ kJ mol J S298 mol K TiCl4(g) -737.2 -802.1 252.3 TiO2(s) -889.1 -944.7 50.2 Provide your answer below: kJ/mol H₂O(g) -228.57 -241.82 188.71 HCl(g) -95.4 -92.5 186.6
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 8QRT
Related questions
Question

Transcribed Image Text:Use standard free energy data from the table below to calculate the standard free energy change for the reaction below at
(298 K).
TiCl4(g) + 2H2O(g) → TiO2 (s) + 4HCl(g)
• Your answer should include three significant figures.
Substance AG mol
KJ
ΔΗ
kJ
mol
J
S298 mol K
TiCl4(g) -737.2
-802.1
252.3
TiO2(s) -889.1 -944.7
50.2
Provide your answer below:
kJ/mol
H₂O(g) -228.57 -241.82 188.71
HCl(g)
-95.4 -92.5
186.6
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