Count the significant digits in each of these measurements: measurement 0.003600 J number of significant digits -2 - 8.0 x 10 kJ/mol 51800. kg -1 9.9 x 10 mL G
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- Give clear detailed Solution44. Convert 355 kJ to mJ. Express your answer using 3 significant figures. 355 kJ = Answer mJ© Macmillan Learning Perform the calculation and report the answer using the proper number of significant figures. Make sure the answer is rounded correctly. 1.012 × 10-³ J = (0.016456 g) (298.3682 298.3567) K g. K
- Part A An electron acquires 6.60x10-16 J of kinetic energy when it is accelerated by an electric field from plate A to plate B What is the potential difference between the plates? Express your answer to three significant figures and include the appropriate units. HA AV = Value UnitsConvert 780. J to kJQ5: 1.44 grams of a sample of marble (impure calcium carbonate) dissolved in 40 ml of 1.0 normality (N) of hydrochloric acid, then add an amount of distilled water to the resulting solution, and its volume became 100 ml, it was found that 25 ml of this resulting solution (mixture) needs 19 ml of 0.2 normality (N) NaOH solution. Calculate the normality (mole/L) of the mixture solution and then calculate the percentage of pure calcium carbonate in this sample. If you know that the molecular weight of pure calcium carbonate is 106 g/mol. *
- Measuring the change in temperature versus time upon addition of a hot metal specimen to 9.53 mL of water with an initial temperature of 27.01 degrees Celsius led to a plot with a line with the equation y= -0.121x + 36.86. Determine the heat absorbed by the water in Joules to two decimal places. Type your answer... 22 odf beriment ocx OCXA 13.6 mL sample of polystyrene used in a styrofoam cup weighs 0.222 g What is the density of polystyrene?All of the following metric multiplies and their values are correct EXCEPT: Kilo; 1 x 103 Micro; 1 x 10-6 Milli; 1 x 10-2 Deci; 1 x 10-1
- The specific heat of liquid mercury is 0.140 J g1 c-1. How many joules of heat are needed to raise the temperature of 16.94 g of mercury from 15.0 °C to 34.2 °C? Keep the answer with 2 decimal places. Do not write unit in answer. Type your answer...Convert 36 kcal to J Record the answer in scientific notation (e.g. 2.10E3J)Perform the given calculation. You must round correctly and report the answer with the proper number of significant figures. 1.012×10−3 J/(0.012456 g)(298.3682−298.3567)K