LiCl (s) ---(H2O)---- Li+ (aq) + Cl(aq) 12.1 M = dissolved LiCl Li(OH) (s) -(H2O)----→ Lit (aq) + OH (aq) 5.49 M = dissolved Li(OH) Al(NO3)3 (s) ----- Al+3 --(H2O)-----→ (aq) + 3 NO3¹ (aq) -1
LiCl (s) ---(H2O)---- Li+ (aq) + Cl(aq) 12.1 M = dissolved LiCl Li(OH) (s) -(H2O)----→ Lit (aq) + OH (aq) 5.49 M = dissolved Li(OH) Al(NO3)3 (s) ----- Al+3 --(H2O)-----→ (aq) + 3 NO3¹ (aq) -1
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter13: Acids And Bases
Section: Chapter Questions
Problem 76QAP: A solution of sodium cyanide, NaCN, has a pH of 12.10. How many grams of NaCN are in 425 mL of a...
Question
Calculate "Ksp value for this solubility reactions.
Provide explanations and steps.

Transcribed Image Text:LiCl
(s) ---(H2O)---- Li+ (aq) + Cl(aq)
12.1 M = dissolved LiCl
Li(OH) (s)
-(H2O)----→ Lit (aq) + OH (aq)
5.49 M = dissolved Li(OH)
Al(NO3)3 (s)
-----
Al+3
--(H2O)-----→
(aq) +
3 NO3¹ (aq)
-1
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