The transmission loss function of a power network consisting of 2 generators at different buses can be expressed as follows: Pioss = 0.002P,2 + 0.001P22, where P1, and P2 are the generators' power outputs. If P, = 150 MW, P2 = 100 MW, the penalty factor of bus 1 and 2 are respectively equal to: Select one: a. PF1=2, PF2=1 O b. PF1=1.5, PF2=1.2 O c. None of these O d. PF1=2.5, PF2=1.25 Clear my choice

The transmission loss function of a power network consisting of 2 generators at different buses can be expressed as follows: Pioss = 0.002P,2 + 0.001P22, where P1, and P2 are the generators' power outputs. If P, = 150 MW, P2 = 100 MW, the penalty factor of bus 1 and 2 are respectively equal to: Select one: a. PF1=2, PF2=1 O b. PF1=1.5, PF2=1.2 O c. None of these O d. PF1=2.5, PF2=1.25 Clear my choice

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Power system