The transmission loss function of a power network consisting of 2 generators at different buses can be expressed as follows: Pioss = 0.002P,2 + 0.001P22, where P1, and P2 are the generators' power outputs. If P, = 150 MW, P2 = 100 MW, the penalty factor of bus 1 and 2 are respectively equal to: Select one: a. PF1=2, PF2=1 O b. PF1=1.5, PF2=1.2 O c. None of these O d. PF1=2.5, PF2=1.25 Clear my choice

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter12: Power System Controls
Section: Chapter Questions
Problem 12.13P
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The transmission loss function of a power network consisting of 2 generators at different buses can be expressed as follows: Ploss =
0.002P,2 + 0.001P,2, where P1, and P2 are the generators' power outputs. If P, = 150 MW, P2 = 100 MW, the penalty factor of bus 1 and 2
are respectively equal to:
Select one:
a. PF1=2, PF2=1
O b. PF1=1.5, PF2=1.2
O c. None of these
O d. PF1=2.5, PF2=1.25
Clear my choice
Transcribed Image Text:The transmission loss function of a power network consisting of 2 generators at different buses can be expressed as follows: Ploss = 0.002P,2 + 0.001P,2, where P1, and P2 are the generators' power outputs. If P, = 150 MW, P2 = 100 MW, the penalty factor of bus 1 and 2 are respectively equal to: Select one: a. PF1=2, PF2=1 O b. PF1=1.5, PF2=1.2 O c. None of these O d. PF1=2.5, PF2=1.25 Clear my choice
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