The table below shows the purification of liver lactate dehydrogenase. Purification Table of liver LDH Step Volume DEAE-Sephadex 5'AMP-Sepharose (mL) Crude Extract 200 Ammonium Sulfate 100 112 40 LDH activity (Units/mL) (mg/mL) [Protein] 47.0 50.00 90.0 63.00 51.0 1.50 137.0/ 0.4 Calculate the LDH yield for the ammonium sulfate step. Provide answer to one decimal only.
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- Chitinase is a protein that breaks down chitin, a primary component of the cell wall in fungi, scales in fish and exoskeletons of arthropods. The activity of chitinase extracted from a plant was shown to be optimum at pH 5. You were tasked to prepare 300 mL of 150 mM buffer solution for further analysis of the extracted chitinase. REAGENTS Ka 2.5M Acetic acid Solid NaOAc•3H2O [136.08g/mol] 1.76 x 10-5 2.5M NH3 Solid NH4Cl [53.49g/mol] 5.6 x 10-10 2.5M Lactic acid Solid sodium lactate [112.06g/mol] 4.0 x 10-5 5 M HCl 5M NaOH Pls show sol'ns 1. Given the following reagents, give the moles of each component (acid & base).2. What are the mass/volume of the components needed to prepare the buffer? 3. What will the pH of the buffer be if 1mL of 5 M NaOH was added?HEPES, 4-(2-hydro)-1-piperazine ethane sulfonic acid, shown below. fully protonated, has pKa’s of 3.00 and 7.55. It is a commonly used buffer for tissue culture and organ storage during transplantation due in part to its effectiveness over a wide temperature range. One-way oxalic acid can be produced in fungi by hydrolysis of oxaloacetate, an intermediate in the Kreb’s citric acid cycle, to produce oxalic acid and acetic acid. This reaction, shown below, is catalyzed by oxaloacetase. [O2CC(O)CH2CO2] 2− + H2O → C2O44−+ CH3COO− + H+ oxaloacetate oxalic acid acetate In a 1-ml reaction mixture containing 50 mM NaCl, 50 mM HEPES, pH 7.8, 5 mM oxaloacetate and 5 pmol oxaloacetase, complete hydrolysis of the oxaloacetate was achieved in 10 minutes of incubation at 30°C. What was the pH of the reaction mixture at the end of the reaction?Chymotrypsin has the highest affinity for which of the following substrates: Table. The values of KM and kcat for some Enzymes and Substrates Enzyme Chymotrypsin Ки (М) 4.4 x 10-1 8.8 x 10-2 6.6 x 104 Kcat (S-1) 5.1 x 10-2 1.7 x 10-1 1.9 x 102 Substrate N-acetylglycine ethyl ester N-acetylvaline ethyl ester N-acetyltyrosine ethyl ester Catalase H2O2 2.5 x 10-2 1.0 x 107 Urease Urea 2.5 x 10-2 4.0 x 105 OA. N-acetylglycine ethyl ester OB. N-acetylvaline ethyl ester OC. N-acetyltyrosine ethyl ester D. Urea
- Which of these heterocyclic drugs is likely to be the least soluble in water? Use the Fsp³ parameter to decide. OH Tramadol Chemical Formula: C16H25NO2 YOUR OW Pantoprazole Torasemide Chemical Formula: C16H15F2N3O4S Chemical Formula: C16H20N4O3S Temazepam -OH Chemical Formula: C16H13CIN₂O2 Tioconazole Chemical Formula: C16H13C3N₂OS A. Tramadol B. Pantoprazole C. Torasemide D. Temazepam E. ToconazoleThe KM values for the reaction of chymotrypsin with two different substrates are given in the table below. Considering this information, which substrate has the lower apparent affinity for the enzyme? Which substrate is likely to give a lower value for Vmax? Substrate N-acetylvaline ethyl ester N-acetyltyrosine ethyl ester KM (M) 8.8 X 10-² 6.6 X 10-4 N-acetylvaline ethyl ester has the lower apparent affinity for the enzyme; it will also likely to give a lower Vmax: N-acetyltyrosine ethyl ester has the lower apparent affinity for the enzyme; it will also likely to give the lower V₁ max. N-acetylvaline ethyl ester has the lower apparent affinity for the enzyme; N- acetyltyrosine ethyl ester is likely to give the lower Vmax: N-acetyltyrosine ethyl ester has the lower apparent affinity for the enzyme; N- acetylvaline will likely to give the lower Vmax. None of the above statements are correct.Glucosidase I catalyzes hydrolysis of specific glucosidase I is a synthetic trisaccharide, glucose-al-2- glucose-al-3-glucose-a-O(CH₂) #COOCH3. Kinetic measurements oligosaccharides containing glucose. obtained using this trisaccharide as substrate in the deoxynorjirimycin at concentrations of 50 μM (), 100 μM absence (x-x) and presence of the inhibitor 1- A) were used to prepare the (-), and 200 μM (4 Lineweaver-Burk plot below: b) Page 3 12) 7. a) V/V (nmol/hr)-1 1.S 1.0- 0.5 1/Trisaccharide (mM)-! Estimate the values for Vmax and KM for the trisaccharide substrate in the absence of the inhibitor. 0.0 -1.0 0.0 One substrate for 1.0 2.0 Determine whether inhibition by 1-deoxynorjirimycin is competitive, non-competitive or neither.
- Diazepam is converted in vivo to an active metabolite Oxazepam. Explain metabolic transfomation of diazepam to oxazepam. (Provide names of enzymes involved in this transformation. Drawings of structures ofintemediate metabolites is NOT required)uizzes/67365/take Based on the image below, select the correct statements. Note: There may be more than 1 correct response. I Ribose 5-phosphate ribose phosphate pyrophosphokinase (PRPP synthetase) glutamine-PRPP amidotransferase adenylosuccinate synthetase AMP > 5-Phosphoribosylamine I adenylosuccinate PRPP lyase 9 steps Adenylosuccinate AMP IMP <-- ADP - AMP <-- GMP <-- IMP IMP dehydrogenase <- GMP - XMP ADP ATP GMP يمد XMP-glutamine amidotransferase Increased levels of ADP inhibit the production of PRPP. Increased levels of GMP inhibit the production of XMP. O Increased ADP activates PRPP synthase to increase PRPP levels. Increased IMP activates glutamine-PRPP amidotransferase to further increase IMP levels. 8 OBCCalculcate Kcat for PNP substrate for both enzyme concentrations. enzyme volume: 20 ul Bovine Intensince Alkaline phosphatase molecular weight: 140,000 Bovine intenstine Alkaline phosphatase activity: 300 units/ml and 14 units/mg extinction coefficient PNP: 18.5 abs (mM-1 cm-1) Vmax: 0.332 moles/sec a) enzyme 1 concentration: undiluted b) enzyme 2 concentration: 1:1 dilution
- Explain the metabolism, biochemical importance and inborn error of Glycine Phenylalanine, tyrosine - Tryptophan Sulphur containing amino acids.After determining the optimum pH, you are now tasked to determine the inhibitory effects of acarbose, a known anti-diabetic drug which acts an inhibitor of alpha-glucosidase, an intestinal enzyme that hydrolyzes starch to release glucose for absorption and energy usage of the body. You studied the rates of the enzyme at different glycogen concentrations with and without the presence of 0.10 mM acarbose. Below is the summary for this procedure. a) What is the Vmax, in arbitrary units, of the uninhibited reaction (without acarbose)? b) What is the KM , in mM, of the uninhibited reaction (without acarbose)? c) What is the type of inhibition?In some organisms, isoleucine can be synthesized in a multi-step procedure (a series of enzymatic reactions), beginning with a molecule of threonine. Keeping that in mind explain the experimental results below. Amount of endproduct Activity of threonine (isoleucine) deaminase None Low Medium High Very high High Moderate Very low