The population of a particular country consists of three ethnic groups. Each individual belongs to one of the four major blood groups. The accompanying joint probability tablegives the proportions of individuals in the various ethnic group-blood group combinations.1Ethnic Group 23Blood GroupBA0.1000.1410.215 0.202 0.06300.0820.141AB0.009 0.0040.018 0.0050.020Suppose that an individual is randomly selected from the population, and define events by A = {type A selected}, B = {type B selected}, and C = {ethnic group 3 selected}.(a) Calculate P(A), P(C), and P(An C). (Enter your answers to three decimal places.)P(A) =P(C) =P(An C) =(b) Calculate both P(AIC) and P(CIA). (Round your answers to three decimal places.)P(AIC) =P(CIA) =Explain in context what each of these probabilities represents. (Select all that apply.)□ If a person has type A blood, the probability that he is from ethnic group 3 is given by P(CIA).□ If we know that the individual came from ethnic group 3, the probability that he has type A blood is given by P(AIC).If a person has type B blood, the probability that he is from ethnic group 3 is given by P(AIC).□ If a person has type B blood, the probability that he is from ethnic group 3 is given by P(CIA).□ If a person has type A blood, the probability that he is from ethnic group 3 is given by P(AIC).□ If we know that the individual came from ethnic group 3, the probability that he has type A blood is given by P(CIA).(c) If the selected individual does not have type B blood, what is the probability that he or she is from ethnic group 1? (Round your answer to three decimal places.)

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Answered: The population of a particular country…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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In a memory test, the test subjects are given a large number and are asked to memorize it. Historical records show that 80% of test subjects pass the test. To pass the test, a subject must exactly repeat all the digits in the number after two hours. A random sample of 625 people to take the memory test is going to be chosen. Let p be the proportion of people in the sample who pass the test. Answer the following. (If necessary, consult a list of formulas.) (a) Find the mean of P. 0 (b) Find the standard deviation of p. 0 (c) Compute an approximation for P(P >0.84), which is the probability that more than 84% of the people in the sample pass the test. Round your answer to four decimal places. 0 X
A manufacturing company that produces laminate for countertops is interested in studying the relationship between the number of hours of training that an employee receives and the number of defects per countertop produced. Ten employees are randomly selected. The number of hours of training each employee has received is recorded and the number of defects on the most recent countertop produced is determined. The results are as follows. Hours of Training Defects per Countertop 1 5 4 1 7 0 3 3 2 5 2 4 5 1 5 2 1 8 6 2 Copy Data The estimated regression line and the standard error are given. Defects per Countertop=6.717822−1.004950(Hours of Training)se=1.229787se=1.229787 Suppose a new employee has had 5 hours of training. What would be the 90% prediction interval for the number of defects per countertop? Round your answer to two decimal places.
Three randomly selected children are surveyed. The ages of the children are 3, 5, and 10. Assume that samples of size n= 2 are randomly selected with replacement from the population of 3, 5, and 10. Listed below are the nine different samples. Complete parts (a) through (d). 3,3 3,5 3,10 5,3 5,5 5,10 10,3 10,5 10,10 . a. For the population, find the proportion of odd numbers. The proportion is (Round to three decimal places as needed) b. Find the proportion of odd numbers of each of the nine samples, then summarize the sampling distribution of the medians in the format of a table representing the probability distribution of the distinct proportion values ce! Sample Proportion Probability Tool (Type integers or simplified fractions.) c. Find the mean of the sampling distribution of the sample proportion of odd numbers. The mean is (Round to three decimal places as needed ) Next Activane
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According to an article in a recently published medical journal, one-third of all sets of triplets consist of all females, one-fourth are all male sets, and the remaining sets are of mixed gender. A simple random sample of 78 sets of triplets born in the past 20 years is obtained from hospital records. The results are presented below. Gender make-up of triplets 1: All female 2: All male 3: Mixed gender Total 10 11 57 78 What would be the null hypothesis for a chi-square test for testing if the claim made in the medical journal is indeed true? Ho: P1 = P2 = P3 = 5/12, where P₁, P2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively Ho: P₁ = 1/3, P2 = 1/4, and p3 = 5/12, where p₁, P2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively Ho: P1 1/4, P2 1/4, and p3 = 5/12, where p₁, P2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively.
According to an article in a recently published medical journal, one-third of all sets of triplets consist of all females, one-fourth are all male sets, and the remaining sets are of mixed gender. A simple random sample of 78 sets of triplets born in the past 20 years is obtained from hospital records. The results are presented below. Gender make-up of triplets 1: All female 2: All male 3: Mixed gender Total 10 11 57 78 What would be the null hypothesis for a chi-square test for testing if the claim made in the medical journal is indeed true? Group of answer choices H0: p1 = 1/3, p2 = 1/4, and p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively H0: p1 = p2 = p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively H0: p1 = 1/4, p2 = 1/4, and p3 = 5/12, where p1, p2, and p3 represent the proportions of all…
Below are the numbers of patients classified as underweight, normal weight, overweight and obese according to their diabetes status. If a patient is selected at random: What proportion of normal weight patients are not diabetic? What proportion of patients are normal weight or underweight? Underweight Normal Weight Overweight Obese Row Totals Diabetic 8 34 65 43 150 Not Diabetic 12 85 93 40 230 Column Totals 20 119 158 83 380
A poll was taken of 12,729 working adults aged 40-70 to determine their level of education. The participants were classified by sex and by level of education. The results are shown below. Education Level Male Female Total High School or Less 3577 2472 6049 Bachelor's Degree 3037 2585 5622 Master's Degree 480 464 944 Ph.D. 66 48 114 Total 7160 5569 12,729 A person is selected at random. Compute the following probabilities. b) What is the probability that the selected person does not have a Master's degree, given that he is male? What is the probability that the selected person has a Ph.D., given that she is female?

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