What would be the null hypothesis for a chi-square test for testing if the claim made in the medical journal is indeed true? Group of answer choices H0: p1 = 1/3, p2 = 1/4, and p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively H0: p1 = p2 = p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively H0: p1 = 1/4, p2 = 1/4, and p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively.
What would be the null hypothesis for a chi-square test for testing if the claim made in the medical journal is indeed true? Group of answer choices H0: p1 = 1/3, p2 = 1/4, and p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively H0: p1 = p2 = p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively H0: p1 = 1/4, p2 = 1/4, and p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively.
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 4ECP: Show that the probability of drawing a club at random from a standard deck of 52 playing cards is...
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Question
According to an article in a recently published medical journal, one-third of all sets of triplets consist of all females, one-fourth are all male sets, and the remaining sets are of mixed gender. A simple random sample of 78 sets of triplets born in the past 20 years is obtained from hospital records. The results are presented below.
Gender make-up of triplets |
|
1: All female |
2: All male |
3: Mixed gender |
Total |
10 |
11 |
57 |
78 |
What would be the null hypothesis for a chi-square test for testing if the claim made in the medical journal is indeed true?
Group of answer choices
H0: p1 = 1/3, p2 = 1/4, and p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively
H0: p1 = p2 = p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively
H0: p1 = 1/4, p2 = 1/4, and p3 = 5/12, where p1, p2, and p3 represent the proportions of all female, all male, and mixed gender triplets, respectively.
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