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Kellogg's Froot Loops cereal comes in six colors: orange, yellow, purple, red, blue, and green. Charise randomly selected 120 loops and noted the color of each. Shown in the table are her data. Color Count Orange 28 Yellow 21 Purple 16 Red 25 Blue 14 Green 16 We want to test Ho: Froot Loops contain an equal proportion of each flavor versus Ha: Froot Loops do not contain an equal proportion of each flavor. Use a chi-square goodness-of-fit test to compute a test statistic and P-value. Do these data provide convincing evidence at the 5% significance level that Kellogg's Froot Loops do not contain an equal proportion of each color? Because the P-value of 0.3495 < 0.05, we cannot reject the null hypothesis. We conclude that Froot Loops do contain an equal proportion of each color. Because the P-value of 0.1618 > 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.2455 < 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.2118 < 0.05, we reject the null hypothesis in favor of the alternate. We conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.7222 > 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color.

Kellogg's Froot Loops cereal comes in six colors: orange, yellow, purple, red, blue, and green. Charise randomly selected 120 loops and noted the color of each. Shown in the table are her data. Color Count Orange 28 Yellow 21 Purple 16 Red 25 Blue 14 Green 16 We want to test Ho: Froot Loops contain an equal proportion of each flavor versus Ha: Froot Loops do not contain an equal proportion of each flavor. Use a chi-square goodness-of-fit test to compute a test statistic and P-value. Do these data provide convincing evidence at the 5% significance level that Kellogg's Froot Loops do not contain an equal proportion of each color? Because the P-value of 0.3495 < 0.05, we cannot reject the null hypothesis. We conclude that Froot Loops do contain an equal proportion of each color. Because the P-value of 0.1618 > 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.2455 < 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.2118 < 0.05, we reject the null hypothesis in favor of the alternate. We conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.7222 > 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Kellogg's Froot Loops cereal comes in six colors: orange, yellow, purple, red, blue, and green. Charise randomly selected 120 loops and noted the color of each. Shown in the table are her data. Color Count Orange 28 Yellow 21 Purple 16 Red Blue 25 14 Green 16 We want to test Ho: Froot Loops contain an equal proportion of each flavor versus Ha: Froot Loops do not contain an equal proportion of each flavor. Use a chi-square goodness-of-fit test to compute a test statistic and P-value. Do these data provide convincing evidence at the 5% significance level that Kellogg's Froot Loops do not contain an equal proportion of each color? Because the P-value of 0.3495 < 0.05, we cannot reject the null hypothesis. We conclude that Froot Loops do contain an equal proportion of each color. Because the P-value of 0.1618 > 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.2455 < 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.2118 < 0.05, we reject the null hypothesis in favor of the alternate. We conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.7222 > 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color.
Transcribed Image Text:Kellogg's Froot Loops cereal comes in six colors: orange, yellow, purple, red, blue, and green. Charise randomly selected 120 loops and noted the color of each. Shown in the table are her data. Color Count Orange 28 Yellow 21 Purple 16 Red Blue 25 14 Green 16 We want to test Ho: Froot Loops contain an equal proportion of each flavor versus Ha: Froot Loops do not contain an equal proportion of each flavor. Use a chi-square goodness-of-fit test to compute a test statistic and P-value. Do these data provide convincing evidence at the 5% significance level that Kellogg's Froot Loops do not contain an equal proportion of each color? Because the P-value of 0.3495 < 0.05, we cannot reject the null hypothesis. We conclude that Froot Loops do contain an equal proportion of each color. Because the P-value of 0.1618 > 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.2455 < 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.2118 < 0.05, we reject the null hypothesis in favor of the alternate. We conclude that Froot Loops do not contain an equal proportion of each color. Because the P-value of 0.7222 > 0.05, we cannot reject the null hypothesis. We cannot conclude that Froot Loops do not contain an equal proportion of each color.
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