Drop down options are as follows:a. z test or t testb. u or p, <,>,= or not equal toc. z or t Before the furniture store began its ad campaign, it averaged 130 customers per day. The manager isinvestigating if the average is smaller since the ad came out. The data for the 16 randomly selected dayssince the ad campaign began is shown below:109, 117, 133, 117, 134, 129, 110, 136, 110, 128, 113, 138, 125, 99, 145, 114Assuming that the distribution is normal, what can be concluded at the a = 0.10 level of significance?a. For this study, we should use Select an answerb. The null and alternative hypotheses would be:Но:? vSelect an answer vH1: ? vSelect an answer vc. The test statistic(please show your answer to 3 decimal places.)d. The p-value =(Please show your answer to 4 decimal places.)e. The p-value is ? v af. Based on this, we should Select an answer v the null hypothesis.g. Thus, the final conclusion is that ...O The data suggest that the population mean number of customers since the ad campaign beganis not significantly less than 130 at a = 0.10, so there is insufficient evidence to conclude thatthe population mean number of customers since the ad campaign began is less than 130.O The data suggest the populaton mean is significantly less than 130 at a = 0.10, so there issufficient evidence to conclude that the population mean number of customers since the adcampaign began is less than 130.O The data suggest the population mean is not significantly less than 130 at a = 0.10, so there issufficient evidence to conctude that the population mean number of customers since the adcampaign began is equal to 130.

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Description: Drop down options are as follows:a. z test or t testb. u or p, ,= or not equal toc. z or t Before the furniture store began its ad campaign, it averaged 130 customers per day. The manager isinvestigating if the average is smaller since the ad came

a. For this study , we should use t-test The task here to test whether the population average of customers per day is 130 or less than that. The population standard deviation is unknown, so t-test will be applied. b. The null and alternative hypothesis would be Ho : μ=130H1 : μ<130 For α=0.10, the one tailed t critical value at (n-1)=15 degrees of freedom is 1.341 The test statistics is given by : t=x-μs/n~tn-1x = sample averageμ = Population average=130s = Sample standard deviationn = Sample sizeFrom the data, the sample mean and standard deviation are 122.313 and 12.960 respectively. The test statistics is : t=122.313-13012.960/16=-2.3725≈-2.373 c. The test statistics is t=-2.373 d. The p-value is 0.0157 e. The p-value is less than α f. Based on this we should reject the null hypothesis. g. Thus the final conclusion is that the data suggest that the population mean is significantly less than 130at α=0.10, so there is sufficient evidence to conclude that the population mean number of customers since the ad campaign began is less than 130.

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Before the furniture store began its ad campaign, it averaged 130 customers per day. The manager is investigating if the average is smaller since the ad came out. The data for the 16 randomly selected days since the ad campaign began is shown below: 109, 117, 133, 117, 134, 129, 110, 136, 110, 128, 113, 138, 125, 99, 145, 114 Assuming that the distribution is normal, what can be concluded at the a = 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? Select an answer v H1: Select an answer v c. The test statistic ? (please show your answer to 3 decimal places.)

Before the furniture store began its ad campaign, it averaged 130 customers per day. The manager is investigating if the average is smaller since the ad came out. The data for the 16 randomly selected days since the ad campaign began is shown below: 109, 117, 133, 117, 134, 129, 110, 136, 110, 128, 113, 138, 125, 99, 145, 114 Assuming that the distribution is normal, what can be concluded at the a = 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? Select an answer v H1: Select an answer v c. The test statistic ? (please show your answer to 3 decimal places.)

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Drop down options are as follows:

a. z test or t test

b. u or p, <,>,= or not equal to

c. z or t

Before the furniture store began its ad campaign, it averaged 130 customers per day. The manager is
investigating if the average is smaller since the ad came out. The data for the 16 randomly selected days
since the ad campaign began is shown below:
109, 117, 133, 117, 134, 129, 110, 136, 110, 128, 113, 138, 125, 99, 145, 114
Assuming that the distribution is normal, what can be concluded at the a = 0.10 level of significance?
a. For this study, we should use Select an answer
b. The null and alternative hypotheses would be:
Но:
? v
Select an answer v
H1: ? v
Select an answer v
c. The test statistic
(please show your answer to 3 decimal places.)
d. The p-value =
(Please show your answer to 4 decimal places.)
e. The p-value is ? v a
f. Based on this, we should Select an answer v the null hypothesis.
g. Thus, the final conclusion is that ...
O The data suggest that the population mean number of customers since the ad campaign began
is not significantly less than 130 at a = 0.10, so there is insufficient evidence to conclude that
the population mean number of customers since the ad campaign began is less than 130.
O The data suggest the populaton mean is significantly less than 130 at a = 0.10, so there is
sufficient evidence to conclude that the population mean number of customers since the ad
campaign began is less than 130.
O The data suggest the population mean is not significantly less than 130 at a = 0.10, so there is
sufficient evidence to conctude that the population mean number of customers since the ad
campaign began is equal to 130.

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