D. P(pass/morning) = 0.28 P(pass/afternoon) = 0.53 Conclussion: A student taking the test in the morning has a greater chance of passing it than a student taking it in the afternoon. OA. P(pass morning) 0.37P(pass afternoon) 0.71Conclusion: A student taking the test in the morning has a greaterchance of passing it than a student taking it in the afternoon.B. P(pass morning) 0.28P(pass afternoon) 0.53Conclusion: A student taking the test in the afternoon has agreater chance of passing it than a student taking it in themorning.C. P(pass morning) 0.37P(pass afternoon) - 0.71Conclusion: A student taking the test in the afternoon has agreater chance of passing it than a student taking it in themorning. A group of students was randomly divided into two subgroups. One subgrouptook a test in the morning, and the other took the same test in the afternoon.This table shows the results.PassFailTotalMorning284775Afternoon532275Total8169150Compare the probability that a student will pass the test in the morning withthe probability that a student will pass the test in the afternoon. Draw aconclusion based on your results.

Solution: The result table of the test is Pass Fail Total Morning 28 47 75 Afternoon 53…

bgroup took a test in the morning, and the other took the same test in the afternoon. This table shows the results. Pass Fall Total Morning 28 47 75 Afternoon 53 22 75 Total 81 69 150 Compare the probability that a student will pass the test in the morning with

bgroup took a test in the morning, and the other took the same test in the afternoon. This table shows the results. Pass Fall Total Morning 28 47 75 Afternoon 53 22 75 Total 81 69 150 Compare the probability that a student will pass the test in the morning with

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Lecture(12.8A) A researcher thinks that people have become more anxious when they hear about violent crime in the news. He asked a group of random participants to fill out two questioners. One questionere measured anxiety on a point scale from 1 to 10 with high anxiety resuting in higher scores. The other questionare asked participants to report the incidents of violent crime they had heard about (throuh media or face- to-face cummincation) in the last two weeks. The researcher gave the participants a score based on the total number of incidents reported. (1) What type of test should the researcher use to test this hypothesis.? (2) What would be the null and alternative hypotheses for this study? (Select two answers for each) (a) Z test (b)single sample t test (c)dependent sample t-test (d) independent sample t -test (e) ANOVA (f) Pearson correlation t-test (roe) (g) Chi Square goodness of fit test. (h)Chi Square test for independece (i)Ho: roe<=0…
Q-4)Show all the steps for the problem.
X10.2.21-T Twenty years ago, 56% of parents of children in high school felt it was a serious problem that high school students were not being taught enough math and science. A recent survey found that 247 of 700 parents of children in high school felt it was a serious problem that high school students were not being taught enough math and science. Do parents feel differently today than they did twenty years ago? Use the a=0.01 level of significance. Because npo (1- Po) = 172.5 > 10, the sample size is less than 5% of the population size, and the sample can be reasonably assumed to be random, the requirements for testing the hypothesis are satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? versus H,: Ho: (Type integers or decimals. Do not round.)
Quit smoking: A recent study reported that in a sample of 234 European-American HIV-positive smokers, 105 of them had used a nicotine patch to try to quit smoking, and in a sample of 81 Hispanic-American HIV-positive smokers, 25 had used a nicotine patch. Can you conclude that the proportion of patch users is greater among European-Americans? Let p₁ denote the proportion of European-Americans who used the patch. Use the a=0.01 level of significance. Part 1 of 4 (a) State the appropriate null and alternate hypotheses. Ho: P₁ (Choose one) ▼ P₂ H₁: P₁ (Choose one) P2 This is a (Choose one) test. Part 2 of 4 (b) Find the P-value. Round the answer to four decimal places. P-value= X S Ś
Please answer all parts and write on the website so I can understand or try to make your handwriting readable as much as you can if you prefer to write on paper.
When you post a picture on social media, it seems like your friends randomly "like" the picture. Independent of the quality or the humor of the photo, there seems to be a 25.7% chance of the picture being "liked" for any given picture. Let X represent the number of pictures you post until one is "liked." (X represents the photo number that is actually liked.) Find: P(X>10)
Which z-score has the higher frequency? (a) z = +1.0 or z = +2.3; (b) z = −2.8 or z = −1.7; (c) z = −.70 or z = −.20; (d) z = 0.0 or z = −2.0.
K Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 582 randomly selected adults showed that 57% of them would erase all of their personal information online if they could. Find the value of the test statistic The value of the test statistic is (Round to two decimal places as needed.).