(a) Construct a 95% confidence interval for the average number of minutes per week a student prepares for class. (b) Construct a 95% confidence interval for the average number of minutes per week a student spends on Facebook. (Hint:, Be sure to convert from minutes per day to minutes per week.) (c) Explain why you might expect the population distributions of these two variables to be highly skewed to the right. Do you think this fact makes your confidence intervals invalid? Explain your answer.
(a) Construct a 95% confidence interval for the average number of minutes per week a student prepares for class. (b) Construct a 95% confidence interval for the average number of minutes per week a student spends on Facebook. (Hint:, Be sure to convert from minutes per day to minutes per week.) (c) Explain why you might expect the population distributions of these two variables to be highly skewed to the right. Do you think this fact makes your confidence intervals invalid? Explain your answer.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![rom these data that brown-eyed
students appear more trustworthy compared to their
blue-eyed counterparts? Test the hypothesis that
the average scores for the two groups are the same.
(Software gives k= 77.3.)
7.44 Facebook use in college. Because of Facebook's
popularity among college students, there is a great
deal of interest in the relationship between Facebook
use and academic performance. One study collected-
information on n=
at the relationships among frequency of Facebook use,
participation in Facebook activities, time spent preparing
for class, and overall GPA.4
Students reported preparing for class an average of
706 minutes per week, with a standard deviation of
526 minutes. Students also reported spending an average
of 106 minutes per day on Facebook, with a standard
deviation of 93 minutes; 8% of the students reported
spending no time on Facebook.
1839 undergraduate students to look
(a) Construct a 95% confidence interval for the average
number of minutes per week a student prepares for class.
(b) Construct a 95% confidence interval for the average
number of minutes per week a student spends on
Facebook. (Hint: Be sure to convert from minutes per day
to minutes per week.)
(c) Explain why you might expect the population
distributions of these two variables to be highly
skewed to the right. Do you think this fact makes your
confidence intervals invalid? Explain your answer.
7.45 Possible hiases? Refer to the previous exercise.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c0fe20e-2967-4e24-9b97-4b83c60be721%2F5f8e1d03-98eb-4331-950c-a1fe435cce99%2Fwa9rx6ro_processed.jpeg&w=3840&q=75)
Transcribed Image Text:rom these data that brown-eyed
students appear more trustworthy compared to their
blue-eyed counterparts? Test the hypothesis that
the average scores for the two groups are the same.
(Software gives k= 77.3.)
7.44 Facebook use in college. Because of Facebook's
popularity among college students, there is a great
deal of interest in the relationship between Facebook
use and academic performance. One study collected-
information on n=
at the relationships among frequency of Facebook use,
participation in Facebook activities, time spent preparing
for class, and overall GPA.4
Students reported preparing for class an average of
706 minutes per week, with a standard deviation of
526 minutes. Students also reported spending an average
of 106 minutes per day on Facebook, with a standard
deviation of 93 minutes; 8% of the students reported
spending no time on Facebook.
1839 undergraduate students to look
(a) Construct a 95% confidence interval for the average
number of minutes per week a student prepares for class.
(b) Construct a 95% confidence interval for the average
number of minutes per week a student spends on
Facebook. (Hint: Be sure to convert from minutes per day
to minutes per week.)
(c) Explain why you might expect the population
distributions of these two variables to be highly
skewed to the right. Do you think this fact makes your
confidence intervals invalid? Explain your answer.
7.45 Possible hiases? Refer to the previous exercise.
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