Relative risk is defined to be the ratio of success proportions between two groups. Supposethat a 95% confidence interval for a relative risk is found to be (1.32, 2.62). Wouldyou conclude that the sample data provide strong evidence that the success proportions in thetwo groups differ, and why?No, because the confidence interval is entirely greater than oneYes, because the confidence interval is entirely greater than oneYes, because the confidence interval is entirely greater than zeroNo, because the confidence interval is entirely greater than zero

If the relative risk is 1, it indicates that there is no difference in the risk of the event between…

Answered: Relative risk is defined to be the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose a researcher wants to estimate the population proportion of defective light bulbs. He took a random sample of 800 light bulbs and 40 of them found out to be defective. Suppose the researcher decided to determine the 95% confidence interval estimate of the defective proportion. What is the 95% confidence interval of the defective proportion? (round your answer to three decimal places.)
Based on a random sample of 50 students, the 90 percent confidence interval for the mean amount of money students spend on lunch at a certain high school is found to be ($3.45, $4.15). Which of the following statements is true? (a) 90% of the time, the mean amount of money that all students spend on lunch at this high school will be between $3.45 and $4.15.(b) 90% of all students spend between $3.45 and $4.15 on lunch at this high school.(c) 90% of all random samples of 50 students obtained at this high school would result in a sample mean amount of money students spend on lunch between $3.45 and $4.15.(d) 90% of all random samples of 50 students obtained at this high school would result in a 90% confidence interval that contains the true mean amount of money students spend on lunch.
The dean of students at a large college is interested in learning about their opinions regarding the percentage of first-year students who should be given parking privileges in the main lot. He sends out an email survey to all students about this issue. A large number of first-year students reply but very few sophomores, juniors, and seniors reply. Based on the responses he receives, he constructs a 90% confidence interval for the true proportion of students who believe first-year students should be given parking privileges in the main lot to be (0.71, 0.79). Which of the following may have an impact on the confidence interval, but is not accounted for by the margin of error? response bias O nonresponse bias O sampling variation O undercoverage bias
Suppose the English department of a local university has a total of 105 faculty members. Of this number, 24 (about 23%) are part-time instructors. Is it appropriate to find a confidence interval for the percentage of part-time instructors in the department? Find a 95% confidence interval or explain why you should not find a confidence interval for the percentage of part-time instructors in the English department.
A college professor would like to estimate the proportion of students who pull an "all-nighter," meaning they study all night for an upcoming exam. She selects a random sample of 100 students from her large college and finds that the 99% confidence interval for the true proportion of students who pull an all-nighter is 0.48 to 0.62. Which of these statements is a correct interpretation of the confidence level? O Approximately 99% of all students have pulled an all-nighter. O There is a 99% probability that the true proportion of all students who pull an all-nighter is between 0.48 and 0.62. If many random samples of size 100 are selected from all students at this college, approximately 99% of the intervals would capture the true proportion who pull an all-nighter. C Approximately 99% of the sample proportions of students who pull an all-nighter, based on random samples of size 100 from the population of all students at this college, will fall between 0.48 and 0.62.
Which is true about a 95% confidence interval for a population proportion based on a given sample? A There is a 95% chance that the true sample proportion is in the middle of our interval. There is a 5% chance that our Interval does not contain the population proportion. C The Interval Is wider than a 90% confidence Interval would be. none of these is true.
Most married couples have two or three personality preferences in common. A random sample of 370 married couples found that 130 had three preferences in common. Another random sample of 572 couples showed that 234 had two personality preferences in common. Let p1 be the population proportion of all married couples who have three personality preferences in common. Let p2 be the population proportion of all married couples who have two personality preferences in common. (a) Find a 99% confidence interval for p1 – p2. (Use 3 decimal places.) lower limit upper limit
If two people used the same data and one person made a 90% confidence interval and the other person made a 95% confidence interval for p, which interval would be more narrow? is it; a. The 90% Confidence interval b. The 95% Confidence interval c. We cannot tell from the information alone.
Debbie and Ethan are going to construct confidence intervals from the same simple random sample. Debbie's confidence interval will have a 98% confidence interval and Ethan's will have a 95% confidence interval. A. Which confidence interval, if there is a difference will have a larger margin of error? B. Which confidence interval is more likely to cover the population mean, if there is a difference I am using a Ti84 and need to know how to get the answer.
You want to create a confidence interval for the difference in the percent of people over 40 who took music lessons as children and the percent of people 20-40 who took music lessons as children. You decide to use the Plus Four method. You ask 30 people over 40 and find that 21 of them took music lessons as children. You ask 25 people 20-40 and find that 13 took music lessons as children. Fill in the blanks for what you would put into your calculator's interval function. Have people over 40 be group 1. X1 = n1 = X2 = n2 =
Most married couples have two or three personality preferences in common. A random sample of 362 married couples found that 138 had three preferences in common. Another random sample of 552 couples showed that 218 had two personality preferences in common. Let p1 be the population proportion of all married couples who have three personality preferences in common. Let p2 be the population proportion of all married couples who have two personality preferences in common. (a) Find a 95% confidence interval for p1 – p2. (Use 3 decimal places.)lower limit =upper limit=
In studying his campaign plans, Mr. Singleton wishes to estimate the difference between men's and women's views regarding his appeal as a candidate. He asks his campaign manager to take two random independent samples and find the 90% confidence interval for the difference. A random sample of 610 male voters and 717 female voters was taken. 179 men and 425women favored Mr. Singleton as a candidate. Find this confidence interval. Step 1 of 3: Find the point estimate that should be used in constructing the confidence interval. Round your answer to three decimal places. Step 2 of 3: Find the margin of error. Round your answer to six decimal places. Step 3 of 3: Construct the 90% confidence interval. Round your answers to three decimal places.

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