Relative risk is defined to be the ratio of success proportions between two groups. Supposethat a 95% confidence interval for a relative risk is found to be (1.32, 2.62). Wouldyou conclude that the sample data provide strong evidence that the success proportions in thetwo groups differ, and why?No, because the confidence interval is entirely greater than oneYes, because the confidence interval is entirely greater than oneYes, because the confidence interval is entirely greater than zeroNo, because the confidence interval is entirely greater than zero

If the relative risk is 1, it indicates that there is no difference in the risk of the event between…

Answered: Relative risk is defined to be the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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let the variable T stand for a student t-distributed variable. find the following a. in a sample of 20 students, the t-value to use to determine a 95% confidence interval for a mean b. in a sample of 30 students, the t-value to use to determine a 98% confidence interval for a mean
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A teacher has a large container of blue, red, and green beads. She wants her students to estimate the proportion of red beads. Each student selects 50 beads, counts the number of red beads, and returns the beads to the container. One student sample has 15 red beads. The students are asked to construct a 95% confidence interval for the true proportion of red beads in the container. Are the conditions for inference met? Yes, the conditions for inference are met. No, the 10% condition is not met. No, the randomness condition is not met. No, the Large Counts Condition is not met.
A marketing survey involves product recognition in New York and California. Of 679 New Yorkers surveyed, 256 knew of the product while 208 of 631 Californians knew of the product. Construct a 99% confidence interval for the difference between the two population proportions, P₁-P₂ (where p₁ is the proportion of New Yorkers who knew of the product, and P₂ is the proportion of Californians who knew of the product). Give your answers as decimals, rounded to 3 places after the decimal point (if necessary). 99% confidence interval for P₁ - P2:
What is the effect on the size of the confidence interval if a T score is used instead of a Z score? It causes the interval to be bigger. It has no effect on the interval. It causes the interval to be smaller.
A recent Gallup Poll interviewed a random sample of 1523 adults. Of these, 868 bought a lottery ticket in the past year. The same Gallup Poll asked its 1523 adult respondents and also 501 teens (ages 13 to 17) whether they generally approved of legal gambling: 63% of adults and 52% of teens said yes. The margin of error for a 95% confidence statement about teens would be a. greater than for adults, because the teen sample is smaller.b. less than for adults, because the teen sample is smaller.c. less than for adults, because there are fewer teens in the population.d. the same as for adults, because they both come from the same sample survey.e. Can't say, because it depends on what percent of each population was in the sample.
A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 respondents, 13% chose chocolate pie, and the margin of error was given as + 3 percentage points. Given specific sample data, which confidence interval is wider: the 95% confidence interval or the 80% confidence interval? Why is it wider? Choose the correct answer below. O A. A 95% confidence interval must be wider than an 80% confidence interval because it contains 95% of the true population parameters, while the 80% confidence interval only contains 80% of the true population parameters O B. An 80% confidence interval must be wider than 95% confidence interval in order to be more confident that it captures the true value of the population proportion. OC. A 95% confidence interval must be wider than an 80% confidence interval in order to be more confident that it captures the true value of the population proportion. O D. An 80% confidence interval must be wider than a 95%…
What is the best explanation or solution to the answer?
National statistics show that 23% of men (sample 1) smoke and 18.5% of women (sample 2) do. A random sample of 149 men indicated that 64 were smokers , and of 119 women surveyed , 41 indicated that they smoked. Construct a 95% confidence interval for the true difference in proportions of male and female smokers. Select one: O a. -0.032
A poll found that people from the north now have relatively warm feelings toward people from the south. A poll, conducted by telephone among a random sample of 747 adults, found that 605 of those sampled consider the two regions friends. The margin of error for the poll was plus or minus 2.8 percentage points (for a 0.95 confidence level). Use this information to obtain a 95% confidence interval for the percentage of all northerners who consider the two regions friends. The 95% confidence interval is from % to %. (Type an integer or a decimal rounded to one decimal place as needed.)
A 90% confidence interval for the difference between the proportion of college students who use flash cards for studying and high school students who use flash cards for studying is (0.13, 0.23). Then the Error is +5%. True False
A 90% confidence interval for the average salary of all CEOs in the electronics industry was constructed using the results of a random survey of 45 CEOs. The interval was Give a practical interpretation of the interval. 90% of the sampled CEOs have salaries that fell in the interval $146,132 to $156,381. 90% of all CEOs in the electronics industry have salaries that fall between $146,132 to $156,381. We are 90% confident that the mean salary of the sampled CEOs falls in the interval $146,132 to $156,381. We are 90% confident that the mean salary of all CEOs in the electronics industry falls in the interval $146,132 to $156,381.

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