←A random sample of 5001 adults in a country includes 755 who do not use the Internet. Construct a 95% confidenceinterval estimate of the percentage of adults in the country who do not use the Internet. Based on the result, does itappear that the percentage of adults in the country who do not use the Internet is different from 48%, which was thepercentage in the year 2000?View an example Get more help.31Points: 0 of 1(...)CMConstruct a 95% confidence interval estimate of the percentage of adults in the country who do not use the Internet.%

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A recent survey showed that 42% of US employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 500 companies. Find the 99% confidence interval for the proportion of all companies likely to require higher employee contributions for health care coverage. (Round to four decimal places)
Based on a sample of 1000 adult Americans, USA Today reported that 840 of them preferred cheese on their burgers. Calculate and interpret an 88% confidence interval for the proportion of all adult Americans who prefercheese on their burgers.
Out of 400 people sampled, 276 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids.
An apartment hunter is shopping for either a one-bedroom or two-bedroom apartment in varying apartment buildings. She wants to estimate the additional amount she would have to pay, on average, for a two-bedroom apartment versus a one-bedroom apartment. The table shows the prices, in dollars, for one- and two-bedroom apartments from the nine buildings she visited. A 95% confidence interval for the true mean difference between two-bedroom and one-bedroom apartments for apartment buildings like the ones in the sample was (255.93, 508.51). A friend of the apartment hunter tells her to expect to pay about $500 more per month for a two-bedroom apartment than for a one-bedroom apartment. Does the confidence interval provide evidence for the friend’s claim? A. No, the confidence interval does not contain 0, so the friend’s claim is not plausible. B. No, the confidence interval contains many more numbers below 500 than above 500, so it is unlikely that the friend’s assertion is correct. C.…
in a survey of 692 lesbian, gay, bisexual, or transgender U.S adults 378 said that they consider themselves bisexual. Construct a 90% confidence interval for the population proportion of lesbian, gay, bisexual, or transgender U.S adults who consider themselves bisexual.
Suppose the English department of a local university has a total of 105 faculty members. Of this number, 24 (about 23%) are part-time instructors. Is it appropriate to find a confidence interval for the percentage of part-time instructors in the department? Find a 95% confidence interval or explain why you should not find a confidence interval for the percentage of part-time instructors in the English department.
Out of 600 people sampled, 402 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids.
In a Time/CNN survey, 24% of 205 single women said that they “definitely want to get married.” In the same survey, 27% of 260 men gave that same response. Construct a 99% confidence interval estimate of the difference between the proportion of single women and single men who definitely want to get married. 2. Is there a gender gap on this issue? How do you know?
In a survey of 500 students, 327 said they were planning to stay in town for the holidays. What is the point estimate for the proportion of students staying home for the holidays? Construct the 95% confidence interval for the proportion of students staying home for the holidays. Assume all requirements have been met.
Of 130 adults selected randomly from one town, 25 of them smoke. Construct a 99% confidence interval for the true percentage of all adults in the town that smoke.
In the United States, 1000 residents aged 15 or older were surveyed and 870 replied that they were satisfied with the water quality. The 90% confidence interval estimate of all U.S residents satisfied with their water quality is
A surprising fact indicates that a small proportion of teens use a password on their mobile device. A poll chooses a simple random sample of 120 teens and asks if they use a password on their mobile device. The results showed that 56 of teens in our sample used a password on their mobile device. Find a 90 % confidence interval for the proportion of teens who use a password on their mobile device. Interpret your confidence interval.

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