A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99% confidence interval for the proportion of people that are left-handed.

Q: A survey of 800 women shoppers found that 17% of them shop on impulse what is the 98% confidence…

A: Sol:- To calculate the 98% confidence interval for the proportion of women shoppers who shop on…

Q: A survey of 540 depressed shoppers found at 32% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: A research center survey of 2,384 adults found that 1,868 had bought something online. Of these…

A: From the provided information,Sample size (n) = 2384From which 1247 are weekly online…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: A recent survey showed that among 850 randomly selected subjects who completed 4 years of college,…

A: I'm providing the solution below please do refer it and let me know if you have any queries…

Q: A survey of 400 students at Red Rock College found that 180 planned to take summer classes. Find a…

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Q: The Centers for Disease Control and Prevention reported a survey of randomly selected Americans age…

A: Confidence interval for Proportions : The following is the formula for confidence interval of the…

Q: In a survey of 1005 adults 526 stated construct a 95% confidence interval

A:

Q: Out of 200 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: Of 127 randomly selected adults, 31 were found to have high blood pressure. Construct a 95%…

A: Given that, Of 127 randomly selected adults, 31 were found to have high blood pressure.  X = 31 N =…

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A: Given,n=1037x=643p^=xnp^=6431037=0.6201-p^=1-0.620=0.380α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a survey of 612 randomly selected female college students, 141 report that they had been sexually…

A: Given Information:n=612x=141c=95%=0.95

Q: A random variance survey of 495 adults found that 59 had diabetes. which of the following is a 98%…

A:

Q: n a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A:

Q: Of 219 employees selected randomly from a company, 10% of them commute by carpooling. Construct a…

A: Given Data Sample Size, n = 219 Sample proportion = p̂= 0.10 Significance level, α…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: A survey found that 39 of 66 people who don't drink coffee often have trouble sleeping and 44 of 88…

A: Solution: Let X1 be the number of noncoffee drinkers who have trouble sleeping, n1 be the sample…

Q: 82 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval…

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Q: In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to…

A: Given that, In a sports poll, 142 of 500 randomly selected Americans indicated that they consider…

Q: Of 2019 employees selected randomly at a company, 10% of them commute by carpooling. Construct a 90%…

A:

Q: A sample of 421 adults showed that 239 of them are connected to the Internet from home.  Construct…

A: From the provided information, Sample size (n) = 421 From which 239 are connected to the Internet…

Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: From a lake, an unknown proportion of fish have been tagged.  You collect a sample of 100 fish taken…

A:

Q: A student found that in a random sample of 300 people in a town, 105 play sports. Based on this…

A: Given that, X = 105 N = 300 90% confidence level

Q: A research poll of 1501 adults showed that 1051 of respondents believe in global warming. Find a 98%…

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Q: An actuary is interested in estimating the proportion of young adults who plan to have children…

A: We need to construct the 99% confidence interval for the population proportion. We have been…

Q: In a random survey of 2221 North Americans 689 of them had blood type A+. Construct a 94% Confidence…

A:

Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…

A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326

Q: Out of 100 people sampled, 54 had kids. Based on this, construct a 90 % confidence interval for the…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.