andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading at or above their grade level. identify the population proportion that is being estimated, create a 95% confidence interval for the proportion, and interpret the confidence interval

Q: A random sample of 300 college freshmen found that 112 of them own an iPhone.  Find a 95% confidence…

A: Given, Favorable Cases XX = 112112 Sample Size NN = 300300

Q: A student reported a 95% confidence interval of [3.21,4.29] What is the mean of the data set?…

A:

Q: In a random sample of 100 customers, the items that customers purchased were tracked. It was found…

A: Given,sample size(n)=100sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: It is given that, x is 311 and n is 400.

Q: adults in a recent​ year, 742 made a New​ Year's resolution to eat healthier.   Construct​ 90% and​…

A: The value of z at a 90% confidence level is 1.645, which can be found by using the standard normal…

Q: In a survey of 2113 adults in a recent​ year, 741 made a New​ Year's resolution to eat healthier.…

A:

Q: Lindsey selected a random sample of 25 tomatoes at the farmer's market. The 95% confidence interval…

A: When Lindsey selected a random sample of 25 tomatoes at the farmer's market, she was aiming to…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: An accounting firm has 1200 clients. From a random sample of 120 clients, 110 indicated very high…

A: Given : An accounting firm has 1200 clients So,  Population size (N) = 1200 Sample size (n) = 120…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Sample taken for ages 19 to 25 2253 men and 2629 women random sample In which 986 men and 923 women…

Q: A survey of 400 students at Red Rock College found that 180 planned to take summer classes. Find a…

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Q: Using the 99% level of confidence, what is the confidence interval for proportion of students…

A: Let X be the random variable such number of students attending home football games. X = 750 N: Total…

Q: A medical research team conducted a study to test the effect of a cholesterol reducing…

A:

Q: Out of 200 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: sample of 35 students was taken from the local university. These students spent an average of $180…

A:

Q: A random sample of 75 college students of MSU is selected and 16 are found to have motorcycles on…

A: From the given information, The sample size is 75. Out of 75 students, 16 are found to have…

Q: In a survey of 612 randomly selected female college students, 141 report that they had been sexually…

A: Given Information:n=612x=141c=95%=0.95

Q: In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet…

A: We want to calculate the 90% confidence interval for each of the following proportions

Q: A poll conducted randomly in 2014 found that 52% of U.S. adult Twitter users get at least some news…

A: Proportion is 0.52. The standard error 0.024 The absolute value of Zα/2 is 2.5758 using the Excel…

Q: If n=590 and p=0.93, construct a 90% confidence interval.

A: Express the expression for the confidence interval. C.I=p±Z*p(1-p)n Here, Z* is the critical value .…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: A pharmaceutical company is running tests to see how well its new drug lowers cholesterol. Fourteen…

A: d = Initial level - level after 3 months

Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: A survey of 300 women shoppers found that 17% of them shop on impulse. What is the 80% confidence…

A: From the provided information,A survey of 300 women shoppers found that 17% of them shop on impulse.…

Q: In a sample of 300 people, 48 identified as dog owners. Construct a 99% confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of people who are dog owners. The 99%…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: Out of 100 people sampled, 44 have lied to a family member in the past month. Based on this,…

A:

Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: A simple random sample of 500 students at UMass Boston is taken to estimate the percentage of all…

A:

Q: An internet service provider sampled 540 customers and found that 55 of them experienced an…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.