andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading at or above their grade level. identify the population proportion that is being estimated, create a 95% confidence interval for the proportion, and interpret the confidence interval

Q: A random sample of 300 college freshmen found that 112 of them own an iPhone.  Find a 95% confidence…

A: Given, Favorable Cases XX = 112112 Sample Size NN = 300300

Q: As part of the Pew Internet and American Life Project,, researchers conducted two surveys in late…

A: Given: n1= 800 ,x1= 584 n2= 2253 ,x2= 1059 At 95.0 % confidence level , z score= 1.96 Need to find…

Q: A sample of 60 people who were chosen for a sample had an average IQ score of 105. If the population…

A: From the given, x¯ (mean IQ score from sample)=105n (sample size)=60σ (population SD of IQ…

Q: When Mendel conducted his famous genetics experiment with peas, one sample of offspring consisted of…

A: Obtain the 95% confidence interval estimate of the percentage of yellow peas. The 95% confidence…

Q: In a random sample of 100 customers, the items that customers purchased were tracked. It was found…

A: Given,sample size(n)=100sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: According to a Harris Interactive survey of 2401 adults conducted in April 2009, 25% of adults do…

A:

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: It is given that, x is 311 and n is 400.

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: A poll reported that only 507 out of a total of 1809 adults in a particular region said they had a​…

A: The sampled no. of adults, i.e., the sample size, n=1809. The no. of sampled adults who expressed a…

Q: The average IQ score of an individual is 100. In a study based on a random sample of 1,000 high…

A:

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: In a random sample of 170 customers, 90 ordered chicken sandwiches for lunch. Construct a 94%…

A:

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Sample taken for ages 19 to 25 2253 men and 2629 women random sample In which 986 men and 923 women…

Q: Using the 99% level of confidence, what is the confidence interval for proportion of students…

A: Let X be the random variable such number of students attending home football games. X = 750 N: Total…

Q: Suppose a random sample of 142 graduates admissions officers were asked what role scores on…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: A department chair wanted to know whose students performed better on a common pass/fail final exam:…

A: p1 :  proportion of students passed in smith's  class p2 :  proportion of students passed in Jones's…

Q: In a survey of 612 randomly selected female college students, 141 report that they had been sexually…

A: Given Information:n=612x=141c=95%=0.95

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 500…

A:

Q: What is the value of Z for this confidence interval?

A: Given,sample size(n)=14795no.of people who said yes=2219no.of people who said no =12576

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying…

A: Solution: Given that, Estimate the proportion of students on her campus who eat cauliflower n=20 #…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: The 95​% confidence interval for the proportion that express a great deal of confidence or quite a…

A: A poll reported that only 645 out of a total of 2029 adults in a particular region said they had a​…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: In a survey of 2334 adults in a recent​ year,1370 say they have made a New​ Year's resolution.…

A: Given n=2334 X=1370

Q: Out of 100 people sampled, 44 have lied to a family member in the past month. Based on this,…

A:

Q: A research institute poll asked respondents if they felt vulnerable to identify a theft. In the poll…

A: Given,n=1000x=501p^=xnp^=5011000=0.5011-p^=1-0.501=0.499α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a random sample of 600 adults, 270 described themselves as vegetarians. Construct a 99%…

A: In a random sample of 600 adults, 270 described themselves as vegetarians.

Q: From a lake, an unknown proportion of fish have been tagged.  You collect a sample of 100 fish taken…

A:

Q: A random survey of 36 airline passengers indicates that twelve have never flown before. Find a 95%…

A: We have given that,  Sample size (n) = 36 and favorable cases         (X) = 12 Then,  We Will find…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: The manager at Bell’s Gym wants to know the proportion of members who use the Cardio Machines. A…

A: DETAILED SOLUTION IS PROVIDED BELOWExplanation:

Q: In a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: GIVEN DATA : Total number of golfers are 2480, Number of left handed golfer are 372        TO FIND :…

Q: Find the margin of error for the​ 99% confidence interval used to estimate the population…

A: p^ : Sample Proportion 35% of the patients showed improvement. So, probability that a patient shows…

Q: Of 102 randomly selected adults, 42 were found to have high blood pressure. A 90% confidence…

A:

Q: Find the margin of error for the​ 99% confidence interval used to estimate the population…

A: The random variable X follows normal distribution. The sample size is 1100. The proportion value is…

Q: Assume a nationwide random survey of 800 adults asked about attitudes toward “alternative medicine”…

A: We have given that,  Sample size (n) = 800 and Favorable cases (X) =448 Then,  We will find the 99%…

Q: A poll commissioned by the Center on Addiction and Substance Abuse at Columbia University found that…

A: Given that, X = 1340 N = 2000 98% confidence level

Q: poll reported that only 645 out of a total of 2029 adults in a particular region said they had a​…

A: According to the given information in this question We need to construct 80% confidence interval

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.