ppose a data set of 4,000 observations (n-4,000) was analyzed using OLS to examine the factors influencing students college grade por erages. The regression results are as follows, with standard errors in parentheses: colgpa 1.550 +0.0010 sat- 0.03 hapere-0.05 haize +-0.007 haize (0.00) (0.0000) (0.0007) (0.01) (0.001) where colgpa- GPA in college sat score on the SAT exam hspere-percentile in high school graduating class haize-size of graduating class, in hundreds 11-4,000 -0.254 R-0.253 -0.45 The predicted college GPA for someone who scored 1,120 on the SAT and graduated in the 27th percentile of his or her 700-person high school graduating class, is Suppose you would like to construct a 95% confidence interval around the expected college GPA for someone with aut 1,120, hapere 27, and haize 7. colga 1853+0.0010 sat0 0.03 haperc-0.05 haize0+ 0.007 heise (601) (6000) (0) (0.0 where colgpa-GPA in college sat0 sat-1,120 (0)

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Suppose a data set of 4,000 observations (n - 4,000) was analyzed using OLS to examine the factors influencing students' college grade point
averages. The regression results are as follows, with standard errors in parentheses:
colgpa-1.550 +0.0010 sat-0.03 hspere-0.05 hsize +-0.007 haize
(0.00) (0.00006) (0.0007)
(0.01)
(0.000)
where
colgpa- GPA in college
sat score on the SAT exam
hspere -percentile in high school graduating class
haize size of graduating class, in hundreds
11-4,000
R-0.254
R²-0.253
-0.45
The predicted college GPA for someone who scored 1,120 on the SAT and graduated in the 27th percentile of his or her 700-person high school
graduating class, is
Suppose you would like to construct a 95% confidence interval around the expected college GPA for someone with aat 1,120, hapere 27, and
haize 7.
colga 1853+0.0010 sat
(0,01)
(0.0000)
where
colgpa-GPA in college
sat0 sat-1,120
0.03 Asperc0-0.05 haize0+ 0.007 haize
(0)
(0000)
Transcribed Image Text:Suppose a data set of 4,000 observations (n - 4,000) was analyzed using OLS to examine the factors influencing students' college grade point averages. The regression results are as follows, with standard errors in parentheses: colgpa-1.550 +0.0010 sat-0.03 hspere-0.05 hsize +-0.007 haize (0.00) (0.00006) (0.0007) (0.01) (0.000) where colgpa- GPA in college sat score on the SAT exam hspere -percentile in high school graduating class haize size of graduating class, in hundreds 11-4,000 R-0.254 R²-0.253 -0.45 The predicted college GPA for someone who scored 1,120 on the SAT and graduated in the 27th percentile of his or her 700-person high school graduating class, is Suppose you would like to construct a 95% confidence interval around the expected college GPA for someone with aat 1,120, hapere 27, and haize 7. colga 1853+0.0010 sat (0,01) (0.0000) where colgpa-GPA in college sat0 sat-1,120 0.03 Asperc0-0.05 haize0+ 0.007 haize (0) (0000)
The predicted college GPA for someone who scored 1,120 on the SAT and graduated in the 27th percentile of his or her 700-person high school
graduating class, is
Suppose you would like to construct a 95% confidence interval around the expected college GPA for someone with sat= 1,120, hspere 27, and
hsize=7.
colgpa 1.853+0.0010 sato- 0.03 hsperc0-0.05 heize0+-0.007 hsized
(0.01) (0.006)
(7)
where
colgpa- GPA in college
sato-sat-1,120
hspered-hapere-27
haize0- haize-7
-4,000
R-0.254
-0.253
-0.45
Hint: The 95% critical value of the t distribution is 1.96.
(0.01)
(0.001)
The confidence interval around this expected value of college GPA would be
1.96x
Now suppose you would like to construct a 95% confidence interval around the college GPA for someone with sat 1,120, haperc = 27, and
haize 7, and not just the expected value of college GPA for these values of the explanatory variables.
This confidence interval around this value of college GPA would be
1.96x
Transcribed Image Text:The predicted college GPA for someone who scored 1,120 on the SAT and graduated in the 27th percentile of his or her 700-person high school graduating class, is Suppose you would like to construct a 95% confidence interval around the expected college GPA for someone with sat= 1,120, hspere 27, and hsize=7. colgpa 1.853+0.0010 sato- 0.03 hsperc0-0.05 heize0+-0.007 hsized (0.01) (0.006) (7) where colgpa- GPA in college sato-sat-1,120 hspered-hapere-27 haize0- haize-7 -4,000 R-0.254 -0.253 -0.45 Hint: The 95% critical value of the t distribution is 1.96. (0.01) (0.001) The confidence interval around this expected value of college GPA would be 1.96x Now suppose you would like to construct a 95% confidence interval around the college GPA for someone with sat 1,120, haperc = 27, and haize 7, and not just the expected value of college GPA for these values of the explanatory variables. This confidence interval around this value of college GPA would be 1.96x
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