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The equilibrium constant, K, for the following reaction is 1.80x10² at 698 K. ? 2HI(g) H₂(g) + 1₂(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.330 M HI, 4.43x10-2 M H₂ and 4.43x10-2 M 1₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.69x10-2 mol of H₂(g) is added to the flask? [HI] = [H₂] = [1₂] = M M M

The equilibrium constant, K, for the following reaction is 1.80x10² at 698 K. ? 2HI(g) H₂(g) + 1₂(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.330 M HI, 4.43x10-2 M H₂ and 4.43x10-2 M 1₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.69x10-2 mol of H₂(g) is added to the flask? [HI] = [H₂] = [1₂] = M M M

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter15: Principles Of Chemical Reactivity: Equilibria
Section: Chapter Questions
Problem 6PS: The equilibrium constant Kc, for the reaction 2 NOCI(g) 2 NO(g) + Cl2(g) is 3.9 103 at 300 C. A...
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The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H₂(g) + 1₂(g) ? An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.330 M HI, 4.43×10-² M H₂ and 4.43×10-2 M 1₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.69x10-2 mol of H₂(g) is added to the flask? [HI] = [H₂] = [1₂] = ΣΣΣ
Transcribed Image Text:The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H₂(g) + 1₂(g) ? An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.330 M HI, 4.43×10-² M H₂ and 4.43×10-2 M 1₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.69x10-2 mol of H₂(g) is added to the flask? [HI] = [H₂] = [1₂] = ΣΣΣ
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