The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K. PCl5 (g) PCl3 (g) + Cl2 (g) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.159 M PCl5, 4.37×10-2 M PCl3 and 4.37×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.83×10-2 mol of PCl3(g) is added to the flask?

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Q: The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K. PCl5 (g) ---> PCl3…

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Q: The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g)…

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