The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K.PCl5(g) PCl3(g) + Cl2(g)An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.188 M PCl5, 4.74×10-2 M PCl3 and 4.74×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.48×10-2 mol of Cl2(g) is added to the flask? [PCl5]=M[PCl3]=M[Cl2]=MPlease help me slove this correctly !

If the reaction of forward direction is equal to the reaction of backward direction, the reaction…

Answered: The equilibrium constant, K, for the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The equilibrium constant, K, for the following reaction is 1.20×10^-2 at 500 K.

PCl₅(g) PCl₃(g) + Cl₂(g)

An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.188 M PCl₅, 4.74×10^-2 M PCl₃ and 4.74×10^-2 M Cl₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.48×10^-2 mol of Cl₂(g) is added to the flask?

[PCl₅]	=	M
[PCl₃]	=	M
[Cl₂]	=	M

Please help me slove this correctly !

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