Hydrogen iodide decomposes according to the reaction 2HI(g) H₂(g) + 1₂ (8) A sealed 1.50-L container initially holds 0.00623 mol of H₂, 0.00414 mol of I2, and 0.0244 mol of HI at 703 K. When equilibrium is reached, the concentration of H₂ (g) is 0.00524 M. What are the equilibrium concentrations of HI (g) and I₂ (g)? Round each of your answers to 3 significant figures. Dart 1 of 2

Hydrogen iodide decomposes according to the reaction 2HI(g) H₂(g) + 1₂ (8) A sealed 1.50-L container initially holds 0.00623 mol of H₂, 0.00414 mol of I2, and 0.0244 mol of HI at 703 K. When equilibrium is reached, the concentration of H₂ (g) is 0.00524 M. What are the equilibrium concentrations of HI (g) and I₂ (g)? Round each of your answers to 3 significant figures. Dart 1 of 2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Hydrogen iodide decomposes according to the reaction: 2 HI(g) = H2(g) + I2(g) At 703 K, a sealed 1.50-L container initially holds 0.00415 M H2, 0.00276 M I2, and 0.0163 M HI When equilibrium is reached, the equilibrium concentration of H2(g) is 0.00467 M. What is the equilibrium concentration of HI(g)? None of these 0.00328 M 0.00052 M 0.0158 M 0.0173 M 0.0153 M
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