At equilibrium, the concentrations in this system were found to be [N₂] = [0₂] = 0.300 M and [NO] = 0.500 M. N₂(g) + O₂(g) 2 NO(g) If more NO is added, bringing its concentration to 0.800 M, what will the final concentration of NO be after equilibrium is re-established? 0.0818 [NO] final = M Incorrect
At equilibrium, the concentrations in this system were found to be [N₂] = [0₂] = 0.300 M and [NO] = 0.500 M. N₂(g) + O₂(g) 2 NO(g) If more NO is added, bringing its concentration to 0.800 M, what will the final concentration of NO be after equilibrium is re-established? 0.0818 [NO] final = M Incorrect
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![### Equilibrium Concentration Calculation
**Given Conditions:**
- At equilibrium, the concentrations in this system were found to be:
- \([N_2] = 0.300 \, M\)
- \([O_2] = 0.300 \, M\)
- \([NO] = 0.500 \, M\)
**Chemical Equation:**
\[ N_2(g) + O_2(g) \rightleftharpoons 2NO(g) \]
**Problem Statement:**
If more NO is added, bringing its concentration to \(0.800 \, M\), what will the final concentration of \([NO]\) be after equilibrium is re-established?
**Attempted Solution:**
The final concentration of \([NO]_{final}\) was calculated to be:
\[ [NO]_{final} = 0.0818 \, M \]
**Result:**
This answer is incorrect.
Students are encouraged to review the equilibrium constant expression for this reaction and re-calculate the final concentration of NO after re-establishing equilibrium. Be sure to account for the changes in concentration due to the shift in the reaction as it returns to equilibrium.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F646bd109-e2a6-4c6a-a3ea-1fdf7467c156%2F0e16f441-636b-40ef-9e24-3a2165ed8494%2Faps83ig_processed.png&w=3840&q=75)
Transcribed Image Text:### Equilibrium Concentration Calculation
**Given Conditions:**
- At equilibrium, the concentrations in this system were found to be:
- \([N_2] = 0.300 \, M\)
- \([O_2] = 0.300 \, M\)
- \([NO] = 0.500 \, M\)
**Chemical Equation:**
\[ N_2(g) + O_2(g) \rightleftharpoons 2NO(g) \]
**Problem Statement:**
If more NO is added, bringing its concentration to \(0.800 \, M\), what will the final concentration of \([NO]\) be after equilibrium is re-established?
**Attempted Solution:**
The final concentration of \([NO]_{final}\) was calculated to be:
\[ [NO]_{final} = 0.0818 \, M \]
**Result:**
This answer is incorrect.
Students are encouraged to review the equilibrium constant expression for this reaction and re-calculate the final concentration of NO after re-establishing equilibrium. Be sure to account for the changes in concentration due to the shift in the reaction as it returns to equilibrium.
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