At a certain temperature, the Kp for the decomposition of H₂S is 0.704. H₂S(g) → H₂(g) + S(g) Initially, only H₂S is present at a pressure of 0.260 atm in a closed container. What is the total pressure in the container at equilibrium? Ptotal = atm
At a certain temperature, the Kp for the decomposition of H₂S is 0.704. H₂S(g) → H₂(g) + S(g) Initially, only H₂S is present at a pressure of 0.260 atm in a closed container. What is the total pressure in the container at equilibrium? Ptotal = atm
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 33P
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![At a certain temperature, the K₂ for the decomposition of H₂S is 0.704.
H₂S(g) = H₂(g) + S(g)
Initially, only H₂S is present at a pressure of 0.260 atm in a closed container. What is the total pressure in the container
at equilibrium?
Ptotal =
atm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24814f96-f771-43ed-bd36-58cbc01a040e%2Fef4d0d0d-b1ce-4dfd-a05b-0ff60c06e113%2F84j7ox_processed.png&w=3840&q=75)
Transcribed Image Text:At a certain temperature, the K₂ for the decomposition of H₂S is 0.704.
H₂S(g) = H₂(g) + S(g)
Initially, only H₂S is present at a pressure of 0.260 atm in a closed container. What is the total pressure in the container
at equilibrium?
Ptotal =
atm
![At equilibrium, the concentrations in this system were found to be [N₂] = [O₂] = 0.200 M and [NO] = 0.500 M.
N₂(g) + O₂(g) = 2 NO(g)
If more NO is added, bringing its concentration to 0.800 M, what will the final concentration of NO be after equilibrium
is re-established?
[NO] final
0.550
Incorrect
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24814f96-f771-43ed-bd36-58cbc01a040e%2Fef4d0d0d-b1ce-4dfd-a05b-0ff60c06e113%2Fx493wmj_processed.png&w=3840&q=75)
Transcribed Image Text:At equilibrium, the concentrations in this system were found to be [N₂] = [O₂] = 0.200 M and [NO] = 0.500 M.
N₂(g) + O₂(g) = 2 NO(g)
If more NO is added, bringing its concentration to 0.800 M, what will the final concentration of NO be after equilibrium
is re-established?
[NO] final
0.550
Incorrect
M
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