At a certain temperature, the Kp for the decomposition of H₂S is 0.704. H₂S(g) → H₂(g) + S(g) Initially, only H₂S is present at a pressure of 0.260 atm in a closed container. What is the total pressure in the container at equilibrium? Ptotal = atm

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At a certain temperature, the K₂ for the decomposition of H₂S is 0.704.
H₂S(g) = H₂(g) + S(g)
Initially, only H₂S is present at a pressure of 0.260 atm in a closed container. What is the total pressure in the container
at equilibrium?
Ptotal =
atm
Transcribed Image Text:At a certain temperature, the K₂ for the decomposition of H₂S is 0.704. H₂S(g) = H₂(g) + S(g) Initially, only H₂S is present at a pressure of 0.260 atm in a closed container. What is the total pressure in the container at equilibrium? Ptotal = atm
At equilibrium, the concentrations in this system were found to be [N₂] = [O₂] = 0.200 M and [NO] = 0.500 M.
N₂(g) + O₂(g) = 2 NO(g)
If more NO is added, bringing its concentration to 0.800 M, what will the final concentration of NO be after equilibrium
is re-established?
[NO] final
0.550
Incorrect
M
Transcribed Image Text:At equilibrium, the concentrations in this system were found to be [N₂] = [O₂] = 0.200 M and [NO] = 0.500 M. N₂(g) + O₂(g) = 2 NO(g) If more NO is added, bringing its concentration to 0.800 M, what will the final concentration of NO be after equilibrium is re-established? [NO] final 0.550 Incorrect M
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