The equilibrium constant, Ke, for the following reaction is 1.80 x 104 at 298 K. NH4 HS(s) NH3 (9) + H₂S(9) If an equilibrium mixture of the three compounds in a 4.73 L container at 298 K contains 2.68 mol of NH4HS(s) and 0.461 mol of NH3, the number of moles of H₂S present is mol.
The equilibrium constant, Ke, for the following reaction is 1.80 x 104 at 298 K. NH4 HS(s) NH3 (9) + H₂S(9) If an equilibrium mixture of the three compounds in a 4.73 L container at 298 K contains 2.68 mol of NH4HS(s) and 0.461 mol of NH3, the number of moles of H₂S present is mol.
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter17: Equilibrium
Section: Chapter Questions
Problem 51QAP: . For the reaction 3O2(g)2O3(g)The equilibrium constant, K, has the value 1.121054at a particular...
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![The equilibrium constant,
Ke, for the following reaction is
1.80 x 104 at 298 K.
NH4 HS(s) NH3 (9) + H₂S(9)
If an equilibrium mixture of the three compounds in a 4.73 L container at 298 K contains 2.68 mol of
NH4HS(s) and 0.461 mol of
NH3, the number of moles of
H₂S present is
mol.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb8d8ce1c-d1ae-4fbf-bbe3-121c6915374e%2F69788557-f6a4-420a-8cd1-4458be2474bf%2Fqossp0h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The equilibrium constant,
Ke, for the following reaction is
1.80 x 104 at 298 K.
NH4 HS(s) NH3 (9) + H₂S(9)
If an equilibrium mixture of the three compounds in a 4.73 L container at 298 K contains 2.68 mol of
NH4HS(s) and 0.461 mol of
NH3, the number of moles of
H₂S present is
mol.
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