At a certain temperature, the equilibrium constant K for the following reaction is 1.1: Cl₂(g) + CHC1₂(g) → HC1(g) + CC14(g) Use this information to complete the following table. Suppose a 43. L reaction vessel is filled with 0.28 mol of Cl₂ and 0.28 mol of CHCI 3. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. HC1(g) +CC14 (9) Cl₂(g) + CHC13 (9) What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 2 C1₂(g) +2CHC13 (9) 2 HC1(g) +2CC14 (9) There will be very little Cl₂ and CHCl3. There will be very little HCI and CCl4. Neither of the above is true. = =

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At a certain temperature, the equilibrium constant K for the following reaction is 1.1:
Cl₂(g) + CHC13(g) → HC1(g) + CC14 (g)
Use this information to complete the following table.
Suppose a 43. L reaction vessel is filled with 0.28 mol of Cl₂ and
0.28 mol of CHCI 3. What can you say about the composition of
the mixture in the vessel at equilibrium?
What is the equilibrium constant for the following reaction?
Round your answer to 2 significant digits.
HCl(g)+CC14 (9)
Cl₂(g) + CHC13 (9)
What is the equilibrium constant for the following reaction?
Round your answer to 2 significant digits.
2 C1₂(g) +2CHC13 (9)
2 HCl(g) +2CC14 (9)
There will be very little Cl₂ and CHCI 3.
There will be very little HCI and CCI4.
Neither of the above is true.
K = 0
K = 0
Transcribed Image Text:At a certain temperature, the equilibrium constant K for the following reaction is 1.1: Cl₂(g) + CHC13(g) → HC1(g) + CC14 (g) Use this information to complete the following table. Suppose a 43. L reaction vessel is filled with 0.28 mol of Cl₂ and 0.28 mol of CHCI 3. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. HCl(g)+CC14 (9) Cl₂(g) + CHC13 (9) What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 2 C1₂(g) +2CHC13 (9) 2 HCl(g) +2CC14 (9) There will be very little Cl₂ and CHCI 3. There will be very little HCI and CCI4. Neither of the above is true. K = 0 K = 0
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