The equilibrium constant, K, for the following reaction is 3.92×10-2 at 531 K. PCl5(g) PCl3(g) + Cl2(g) An equilibrium mixture of the three gases in a 7.63 L container at 531 K contains 0.331 M PCl5, 0.114 M PCl3 and 0.114 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 18.0 L? [PCl5] = M [PCl3] = M [Cl2] = M
The equilibrium constant, K, for the following reaction is 3.92×10-2 at 531 K. PCl5(g) PCl3(g) + Cl2(g) An equilibrium mixture of the three gases in a 7.63 L container at 531 K contains 0.331 M PCl5, 0.114 M PCl3 and 0.114 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 18.0 L? [PCl5] = M [PCl3] = M [Cl2] = M
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The equilibrium constant, K, for the following reaction is 3.92×10-2 at 531 K.
PCl5(g) PCl3(g) + Cl2(g)
An equilibrium mixture of the three gases in a 7.63 L container at 531 K contains 0.331 M PCl5, 0.114 M PCl3 and 0.114 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 18.0 L?
PCl5(g) PCl3(g) + Cl2(g)
An equilibrium mixture of the three gases in a 7.63 L container at 531 K contains 0.331 M PCl5, 0.114 M PCl3 and 0.114 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 18.0 L?
[PCl5] | = | M |
[PCl3] | = | M |
[Cl2] | = | M |
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