The equilibrium constant is 237 at a certain temperature for the reaction N2(g) + O2(g) 2 2NO(g) Calculate the concentrations of all species at equilibrium when 1.62 M of each component is added to a flask. HOW DO WE GET THERE? We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of N, consumed to reach equilibrium. N2(g) + O2(g) = 2NO(g) Initial: 1.62 1.62 1.62 Change: Equilibrium: 1.62–x -x -x +2x 1.62-x 1.62+2x Therefore, [NO]? [N2][O2] K= 237 = (1.62+2x)? (1.62 — х)(1.62 — х) What is the value of x?

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The equilibrium constant is 237 at a certain temperature for the reaction
N2(g) + O2(g) 2 2NO(g)
Calculate the concentrations of all species at equilibrium when 1.62 M of each component is added to a flask.
HOW DO WE GET THERE?
We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of N2 consumed to reach equilibrium.
N2(g)
+ O2(g)
न 2NO(g)
Initial:
1.62
1.62
1.62
Change:
+2x
-X
-x
Equilibrium: 1.62–x
1.62-x
1.62+2x
Therefore,
[NO]?
K= 237 =
[N2][O2]
(1.62+2x)?
(1.62 — х)(1.62 — х)
What is the value of x?
x =
Transcribed Image Text:The equilibrium constant is 237 at a certain temperature for the reaction N2(g) + O2(g) 2 2NO(g) Calculate the concentrations of all species at equilibrium when 1.62 M of each component is added to a flask. HOW DO WE GET THERE? We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of N2 consumed to reach equilibrium. N2(g) + O2(g) न 2NO(g) Initial: 1.62 1.62 1.62 Change: +2x -X -x Equilibrium: 1.62–x 1.62-x 1.62+2x Therefore, [NO]? K= 237 = [N2][O2] (1.62+2x)? (1.62 — х)(1.62 — х) What is the value of x? x =
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