The equilibrium constant is 237 at a certain temperature for the reaction N2(g) + O2(g) 2 2NO(g) Calculate the concentrations of all species at equilibrium when 1.62 M of each component is added to a flask. HOW DO WE GET THERE? We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of N, consumed to reach equilibrium. N2(g) + O2(g) = 2NO(g) Initial: 1.62 1.62 1.62 Change: Equilibrium: 1.62–x -x -x +2x 1.62-x 1.62+2x Therefore, [NO]? [N2][O2] K= 237 = (1.62+2x)? (1.62 — х)(1.62 — х) What is the value of x?
The equilibrium constant is 237 at a certain temperature for the reaction N2(g) + O2(g) 2 2NO(g) Calculate the concentrations of all species at equilibrium when 1.62 M of each component is added to a flask. HOW DO WE GET THERE? We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of N, consumed to reach equilibrium. N2(g) + O2(g) = 2NO(g) Initial: 1.62 1.62 1.62 Change: Equilibrium: 1.62–x -x -x +2x 1.62-x 1.62+2x Therefore, [NO]? [N2][O2] K= 237 = (1.62+2x)? (1.62 — х)(1.62 — х) What is the value of x?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The equilibrium constant is 237 at a certain temperature for the reaction
N2(g) + O2(g) 2 2NO(g)
Calculate the concentrations of all species at equilibrium when 1.62 M of each component is added to a flask.
HOW DO WE GET THERE?
We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of N2 consumed to reach equilibrium.
N2(g)
+ O2(g)
न 2NO(g)
Initial:
1.62
1.62
1.62
Change:
+2x
-X
-x
Equilibrium: 1.62–x
1.62-x
1.62+2x
Therefore,
[NO]?
K= 237 =
[N2][O2]
(1.62+2x)?
(1.62 — х)(1.62 — х)
What is the value of x?
x =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3216a391-9091-4165-86c6-f10847a236cf%2F1a758867-c053-42e8-abd6-fdfff8d4433d%2F0egou2f_processed.png&w=3840&q=75)
Transcribed Image Text:The equilibrium constant is 237 at a certain temperature for the reaction
N2(g) + O2(g) 2 2NO(g)
Calculate the concentrations of all species at equilibrium when 1.62 M of each component is added to a flask.
HOW DO WE GET THERE?
We will define the change in the concentrations to reach equilibrium in terms of x. Let x equal the number of moles per liter of N2 consumed to reach equilibrium.
N2(g)
+ O2(g)
न 2NO(g)
Initial:
1.62
1.62
1.62
Change:
+2x
-X
-x
Equilibrium: 1.62–x
1.62-x
1.62+2x
Therefore,
[NO]?
K= 237 =
[N2][O2]
(1.62+2x)?
(1.62 — х)(1.62 — х)
What is the value of x?
x =
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