At a certain temperature, the equilibrium constant K for the following reaction is 393.: H₂(g) + I₂(g) → 2 HI(g) Use this information to complete the following table. There will be very little H₂ and I₂. Suppose a 50. L reaction vessel is filled with 0.70 mol of H₂ and 0.70 mol of I2. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little HI. Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. K = 0 2 HI(g) H₂(g) + 1₂ (9) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. K = -0 3 H₂(g)+31₂(9) 6 HI(g)

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At a certain temperature, the equilibrium constant K for the following reaction is 393.:
H₂(g) + 1₂(g) → 2 HI(g)
Use this information to complete the following table.
There will be very little H₂ and I2.
Suppose a 50. L reaction vessel is filled with 0.70 mol of H₂ and
0.70 mol of I2. What can you say about the composition of the
mixture in the vessel at equilibrium?
There will be very little HI.
Neither of the above is true.
What is the equilibrium constant for the following reaction?
Round your answer to 3 significant digits.
K = 0
2 HI(g)
H₂(g) + 1₂ (9)
What is the equilibrium constant for the following reaction?
Round your answer to 3 significant digits.
K =
3 H₂(9)+31₂(9)
6 HI(g)
ܢܢ
Transcribed Image Text:At a certain temperature, the equilibrium constant K for the following reaction is 393.: H₂(g) + 1₂(g) → 2 HI(g) Use this information to complete the following table. There will be very little H₂ and I2. Suppose a 50. L reaction vessel is filled with 0.70 mol of H₂ and 0.70 mol of I2. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little HI. Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. K = 0 2 HI(g) H₂(g) + 1₂ (9) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. K = 3 H₂(9)+31₂(9) 6 HI(g) ܢܢ
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