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The equilibrium constant, K, for the following reaction is 5.10x10 at 548 K. NH,CI(s) NH3(g) + HCl(g) An equilibrium mixture of the solid and the two gases in a 1.00 L flask at 548 K contains 0.394 mol NH CI, 2.26×103 M NH, and 2.26x10 M HCL If the concentration of HCIg) is suddenly increased to 3.58x103 M, what will be the concentrations of the two gases once equilibrium has been reestablished? [NH3] =| [HCI] = | M M

The equilibrium constant, K, for the following reaction is 5.10x10 at 548 K. NH,CI(s) NH3(g) + HCl(g) An equilibrium mixture of the solid and the two gases in a 1.00 L flask at 548 K contains 0.394 mol NH CI, 2.26×103 M NH, and 2.26x10 M HCL If the concentration of HCIg) is suddenly increased to 3.58x103 M, what will be the concentrations of the two gases once equilibrium has been reestablished? [NH3] =| [HCI] = | M M

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The equilibrium constant, K, for the following reaction is 5.10x10° at 548 K. NH,CI(3) NH,(g) + HCIg) An equilibrium mixture of the solid and the two gases in a 1.00 L flask at 548 K contains 0.394 mol NH,CI, 2.26x10 M NH, and 2.26x10 M HCL If the concentration of HCI(g) is suddenly increased to 3.58x10 M, what will be the concentrations of the two gases once equilibrium has been reestablished? [NH3 = M [HCI] M !!
Transcribed Image Text:The equilibrium constant, K, for the following reaction is 5.10x10° at 548 K. NH,CI(3) NH,(g) + HCIg) An equilibrium mixture of the solid and the two gases in a 1.00 L flask at 548 K contains 0.394 mol NH,CI, 2.26x10 M NH, and 2.26x10 M HCL If the concentration of HCI(g) is suddenly increased to 3.58x10 M, what will be the concentrations of the two gases once equilibrium has been reestablished? [NH3 = M [HCI] M !!
Expert Solution
Step 1

The equilibrium reaction taking place is given as,

=> NH4Cl (s) ⇔ NH3 (g) + HCl (g)                              K = 5.10 × 10-6

Given: Initial equilibrium concentration of NH3 = 2.26 × 10-3 M

Initial equilibrium concentration of HCl = 2.26 × 10-3 M

And the concentrationo of HCl is increased to 3.58 × 10-3 M.

 

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