5. The following reaction begins initially with 0.500 mol of H₂ and 0.500 mol of Br₂ in a 2.0 L flask. The reaction mixture has K = 64 at 427 °C. What are the equilibrium concentrations of each species (in M to two decimal places) at this temperature? H₂(g) + Br₂(g) = 2HBr(g) A: 0.05, 0.05, 0.40
5. The following reaction begins initially with 0.500 mol of H₂ and 0.500 mol of Br₂ in a 2.0 L flask. The reaction mixture has K = 64 at 427 °C. What are the equilibrium concentrations of each species (in M to two decimal places) at this temperature? H₂(g) + Br₂(g) = 2HBr(g) A: 0.05, 0.05, 0.40
Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Equilibrium Concentration Calculation:**
**Problem Statement:**
5. The following reaction begins initially with 0.500 mol of H₂ and 0.500 mol of Br₂ in a 2.0 L flask. The reaction mixture has Kc = 64 at 427 °C. What are the equilibrium concentrations of each species (in M to two decimal places) at this temperature?
\[ \text{H}_2(g) + \text{Br}_2(g) \rightleftharpoons 2\text{HBr}(g) \]
**Solution:**
**Given Data:**
- Initial moles of H₂ = 0.500 mol
- Initial moles of Br₂ = 0.500 mol
- Volume of the flask = 2.0 L
- Equilibrium constant, Kc = 64
- Temperature = 427 °C
**Equilibrium Concentrations:**
The equilibrium concentrations of each species are given as:
- [H₂] = 0.05 M
- [Br₂] = 0.05 M
- [HBr] = 0.40 M
**Answer (A):** 0.05, 0.05, 0.40
This solution involves calculating the changes in concentration due to the reaction reaching equilibrium and applying the expression for Kc to solve for these equilibrium concentrations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e77b376-6a5c-4963-870c-f49a6e984799%2F03e351f1-11ed-4372-b091-15059478fde6%2Fhpqdp3r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Equilibrium Concentration Calculation:**
**Problem Statement:**
5. The following reaction begins initially with 0.500 mol of H₂ and 0.500 mol of Br₂ in a 2.0 L flask. The reaction mixture has Kc = 64 at 427 °C. What are the equilibrium concentrations of each species (in M to two decimal places) at this temperature?
\[ \text{H}_2(g) + \text{Br}_2(g) \rightleftharpoons 2\text{HBr}(g) \]
**Solution:**
**Given Data:**
- Initial moles of H₂ = 0.500 mol
- Initial moles of Br₂ = 0.500 mol
- Volume of the flask = 2.0 L
- Equilibrium constant, Kc = 64
- Temperature = 427 °C
**Equilibrium Concentrations:**
The equilibrium concentrations of each species are given as:
- [H₂] = 0.05 M
- [Br₂] = 0.05 M
- [HBr] = 0.40 M
**Answer (A):** 0.05, 0.05, 0.40
This solution involves calculating the changes in concentration due to the reaction reaching equilibrium and applying the expression for Kc to solve for these equilibrium concentrations.
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