The elastic bar from Problem 1 spins with angular velocity w about an axis, as shown in the figure below. The radial acceleration at a generic point x along the bar is a(x) = w²x. Under this radial acceleration, the bar stretches along x with displacement function u(x). The displacement u(x) is governed by the following equations: d √ ♂ (σ(x)) + pa(x) = 0 PDE dx lσ(x) = Edu Hooke's law (2) where σ(x) is the axial stress in the rod, p is the mass density, and E is the (constant) Young's modulus. The bar is pinned on the rotation axis at x = 0 and it is also pinned at x = L. ω → X L 4

Elements Of Electromagnetics
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The elastic bar from Problem 1 spins with angular velocity ω about an axis, as shown in the figure below. The radial acceleration at a generic point x along the bar is a(x) = ω 2 x. Under this radial acceleration, the bar stretches along x with displacement function u(x). The displacement u(x) is governed by the following equations: ( d dx (σ(x)) + ρa(x) = 0 PDE σ(x) = E du dx Hooke’s law (2) where σ(x) is the axial stress in the rod, ρ is the mass density, and E is the (constant) Young’s modulus. The bar is pinned on the rotation axis at x = 0 and it is also pinned at x = L.

 

Determine:
1. Appropriate BCs for this physical problem.
2. The displacement function u(x).
3. The stress function σ(x). 

The elastic bar from Problem 1 spins with angular velocity w about an
axis, as shown in the figure below. The radial acceleration at a generic
point x along the bar is a(x) = w²x. Under this radial acceleration, the
bar stretches along x with displacement function u(x). The displacement
u(x) is governed by the following equations:
d
√ ♂ (σ(x)) + pa(x) = 0 PDE
dx
lσ(x) = Edu
Hooke's law
(2)
where σ(x) is the axial stress in the rod, p is the mass density, and E is
the (constant) Young's modulus. The bar is pinned on the rotation axis
at x = 0 and it is also pinned at x = L.
ω
→ X
L
4
Transcribed Image Text:The elastic bar from Problem 1 spins with angular velocity w about an axis, as shown in the figure below. The radial acceleration at a generic point x along the bar is a(x) = w²x. Under this radial acceleration, the bar stretches along x with displacement function u(x). The displacement u(x) is governed by the following equations: d √ ♂ (σ(x)) + pa(x) = 0 PDE dx lσ(x) = Edu Hooke's law (2) where σ(x) is the axial stress in the rod, p is the mass density, and E is the (constant) Young's modulus. The bar is pinned on the rotation axis at x = 0 and it is also pinned at x = L. ω → X L 4
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