Table 3. Rate of Diffusion Symbol D1 Parameter Result 2cm Distance traveled by ammonia gas Distance traveled by HCl gas Ratio D2 D1: D2 cm Molecular Weight of NH3 MW1 4.12g/mole Molecular Weight of HCI MW2 6g/mole 4.12:6 Ratio V MW1 : V MW2 Write the balanced chemical equation for the reaction.

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p. Graham's Law
Let's say you carried out the following, where you
1. Prepare glass tubing to about a one (1) meter long.
2. Fit corks on both end of the tube (Figure 3). To both end make a 2-cm mark.
NH4OH
HCI
Figure 3
3. Prepare two cotton balls. Immerse one cotton ball in a conc. ammonium hydroxide
solution and the other with conc. hydrochloric acid.
4. Simultaneously place the 2-soaked cotton balls on both ends of the tube. Now, put
the cork back.
5. Observe carefully the formation of a white ring of ammonium chloride. Mark on the
glass tubing the spot where the ring is formed. The distance traveled by the
ammonia gas is from the 2-cm mark to the spot of the ring and that of hydrogen
chloride gas is from the other mark on its side to the ring spot. Measure their
distances.
6. Since the rate multiplied by the time equal to the distance and the time is taken to be
constant, the distance traveled may be substituted for rate, R, in the above equation.
7. Using the data in your activity, calculate the ratio of the rate of diffusion of ammonia
gas to that of hydrogen chloride gas. Compare the result of your calculation with that
obtained from the square root of their molecular weights.
Transcribed Image Text:p. Graham's Law Let's say you carried out the following, where you 1. Prepare glass tubing to about a one (1) meter long. 2. Fit corks on both end of the tube (Figure 3). To both end make a 2-cm mark. NH4OH HCI Figure 3 3. Prepare two cotton balls. Immerse one cotton ball in a conc. ammonium hydroxide solution and the other with conc. hydrochloric acid. 4. Simultaneously place the 2-soaked cotton balls on both ends of the tube. Now, put the cork back. 5. Observe carefully the formation of a white ring of ammonium chloride. Mark on the glass tubing the spot where the ring is formed. The distance traveled by the ammonia gas is from the 2-cm mark to the spot of the ring and that of hydrogen chloride gas is from the other mark on its side to the ring spot. Measure their distances. 6. Since the rate multiplied by the time equal to the distance and the time is taken to be constant, the distance traveled may be substituted for rate, R, in the above equation. 7. Using the data in your activity, calculate the ratio of the rate of diffusion of ammonia gas to that of hydrogen chloride gas. Compare the result of your calculation with that obtained from the square root of their molecular weights.
C. Graham's Law
Table 3. Rate of Diffusion
Parameter
Symbol
Result
Distance traveled by ammonia
gas
Distance traveled by HCI gas
D1
2cm
D2
cm
Ratio
D1: D2
Molecular Weight of NH3
MW1
4.12g/mole
Molecular Weight of HCI
MW2
6g/mole
4.12:6
Ratio
V MW1 : V MW2
Write the balanced chemical equation for the reaction.
Transcribed Image Text:C. Graham's Law Table 3. Rate of Diffusion Parameter Symbol Result Distance traveled by ammonia gas Distance traveled by HCI gas D1 2cm D2 cm Ratio D1: D2 Molecular Weight of NH3 MW1 4.12g/mole Molecular Weight of HCI MW2 6g/mole 4.12:6 Ratio V MW1 : V MW2 Write the balanced chemical equation for the reaction.
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