Can you help me with the number 7 question? Can you explain step by step including the formula (Gay-Lussac’s Law temperature, pressure)? I need to plug in the fraction to give the correct answer. Gas Laws Worksheet**Charles's Law (temperature, volume)**1) A 550.0 mL sample of nitrogen gas is warmed from 77°C to 86°C. Find its new volume if the pressure remains constant. Given: - \( V_1 = 550.0 \, \text{mL} \) - \( T_1 = 77°C = 350 \, \text{K} \) - \( T_2 = 86°C = 359 \, \text{K} \) Formula: \(\frac{V_1}{T_1} = \frac{V_2}{T_2}\) Calculation: \[ V_2 = \frac{550.0 \, \text{mL} \times 359 \, \text{K}}{350 \, \text{K}} = 564 \, \text{mL} \]2) A gas occupies 1.00 L at 0.00°C. What is the volume at 333.0°C? Given: - \( V_1 = 1.00 \, \text{L} \) - \( T_1 = 273 \, \text{K} \) - \( T_2 = 606 \, \text{K} \) Formula: \(\frac{V_1}{T_1} = \frac{V_2}{T_2}\) Calculation: \[ V_2 = \frac{1.00 \, \text{L} \times 606 \, \text{K}}{273 \, \text{K}} = 2.22 \, \text{L} \]**Boyle's Law (pressure, volume)**3) Convert 338 L at 63.0 atm to its new volume at 1.00 atm. Given: - \( V_1 = 338 \, \text{L} \) - \( P_1 = 63.0 \, \text{atm} \) - \( P_2 = 1.00 \, \text{atm} \) Formula: \(P_1 V_1 = P_2 V_2\) Calculation: \[ V

Answered: 12=0,00°2 = 16+ 273) k = 273 k 7) If a…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Can you help me with the number 7 question? Can you explain step by step including the formula (Gay-Lussac’s Law temperature, pressure)? I need to plug in the fraction to give the correct answer.

Gas Laws Worksheet

**Charles's Law (temperature, volume)**

1) A 550.0 mL sample of nitrogen gas is warmed from 77°C to 86°C. Find its new volume if the pressure remains constant.

Given:
- \( V_1 = 550.0 \, \text{mL} \)
- \( T_1 = 77°C = 350 \, \text{K} \)
- \( T_2 = 86°C = 359 \, \text{K} \)

Formula: \(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)

Calculation:
\[
V_2 = \frac{550.0 \, \text{mL} \times 359 \, \text{K}}{350 \, \text{K}} = 564 \, \text{mL}
\]

2) A gas occupies 1.00 L at 0.00°C. What is the volume at 333.0°C?

Given:
- \( V_1 = 1.00 \, \text{L} \)
- \( T_1 = 273 \, \text{K} \)
- \( T_2 = 606 \, \text{K} \)

Formula: \(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)

Calculation:
\[
V_2 = \frac{1.00 \, \text{L} \times 606 \, \text{K}}{273 \, \text{K}} = 2.22 \, \text{L}
\]

**Boyle's Law (pressure, volume)**

3) Convert 338 L at 63.0 atm to its new volume at 1.00 atm.

Given:
- \( V_1 = 338 \, \text{L} \)
- \( P_1 = 63.0 \, \text{atm} \)
- \( P_2 = 1.00 \, \text{atm} \)

Formula: \(P_1 V_1 = P_2 V_2\)

Calculation:
\[
V

Expert Solution

Step 1

Answer:-

This question involves the use of Gay- Lussac law which states that at constant volume, the pressure of the gas is directly proportional to the absolute temperature of the gas. Absolute temperature means the temperature should be in Kelvin. So, firstly temperature is converted to the Kelvin.

P1/P2 = T1/T2

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