3. Under STP conditions what is the density of Oz gas?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Question 3:**

*Under STP conditions, what is the density of O\(_2\) gas?*

**Explanation:**

This question requires understanding Standard Temperature and Pressure (STP) conditions, which are defined as a temperature of 0°C (273.15 K) and a pressure of 1 atm. To find the density of oxygen gas (O\(_2\)) under these conditions, one can use the ideal gas law and the molar volume of a gas at STP.

**Key Concepts:**

- **Molecular Weight of O\(_2\):** Approximately 32.00 g/mol.
- **Molar Volume at STP:** 22.414 L/mol.

**Calculation:**

To calculate the density (\(\rho\)) of O\(_2\) gas:

\[
\rho = \frac{\text{Molar Mass}}{\text{Molar Volume}} = \frac{32.00 \, \text{g/mol}}{22.414 \, \text{L/mol}} \approx 1.429 \, \text{g/L}
\]

Thus, the density of O\(_2\) gas under STP conditions is approximately 1.429 g/L.
Transcribed Image Text:**Question 3:** *Under STP conditions, what is the density of O\(_2\) gas?* **Explanation:** This question requires understanding Standard Temperature and Pressure (STP) conditions, which are defined as a temperature of 0°C (273.15 K) and a pressure of 1 atm. To find the density of oxygen gas (O\(_2\)) under these conditions, one can use the ideal gas law and the molar volume of a gas at STP. **Key Concepts:** - **Molecular Weight of O\(_2\):** Approximately 32.00 g/mol. - **Molar Volume at STP:** 22.414 L/mol. **Calculation:** To calculate the density (\(\rho\)) of O\(_2\) gas: \[ \rho = \frac{\text{Molar Mass}}{\text{Molar Volume}} = \frac{32.00 \, \text{g/mol}}{22.414 \, \text{L/mol}} \approx 1.429 \, \text{g/L} \] Thus, the density of O\(_2\) gas under STP conditions is approximately 1.429 g/L.
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