Use this equation to calculate the percentage of nitrogen in the sample described below.A sample of a new anti-malarial drug with a mass of 0.2394 g was made to undergo a series of reactions that changed all of thenitrogen in the compound into N₂. This gas had a volume of 18.90 mL when collected over water at 23.80 °C and a pressure of746.0 torr. At 23.80 °C, the vapor pressure of water is 22.110 torr. When 6.478 mg of the compound was burned in pure oxygen,17.57 mg of CO2 and 4.319 mg of H₂O were obtained. Show that the following equation can be used to calculate the percentage of nitrogen in a sample having a mass of W grams whenthe N₂ has a volume of V mL and is collected over water at t in °C at a total pressure of P in torr.The vapor pressure of water occurs in the equation as PoH₂0Percentage N=0.04489 xThe equation can be rearranged to give:0.04489 x0.4489 x0.04489 x0.04489 xP – PÅ₂0)V (P PH₂0)W (273 + tc)273 + tcV(P - P₂0)273 + tcV(PH₂0= Percent N x WP)273 + tc273 + tcV(P PH₂0)= Percent N x==WPercent N x WPercent N x W

Given, % N = 0.04489×V(P-P°H2O)W(273+tc)where,V= volume of N2collected over water tc=temperature P=…

Use this equation to calculate the percentage of nitrogen in the sample described below. A sample of a new anti-malarial drug with a mass of 0.2394 g was made to undergo a series of reactions that changed all of the nitrogen in the compound into N₂. This gas had a volume of 18.90 mL when collected over water at 23.80 °C and a pressure of 746.0 torr. At 23.80 °C, the vapor pressure of water is 22.110 torr. When 6.478 mg of the compound was burned in pure oxygen 17.57 mg of CO₂ and 4.319 mg of H₂O were obtained.

Use this equation to calculate the percentage of nitrogen in the sample described below. A sample of a new anti-malarial drug with a mass of 0.2394 g was made to undergo a series of reactions that changed all of the nitrogen in the compound into N₂. This gas had a volume of 18.90 mL when collected over water at 23.80 °C and a pressure of 746.0 torr. At 23.80 °C, the vapor pressure of water is 22.110 torr. When 6.478 mg of the compound was burned in pure oxygen 17.57 mg of CO₂ and 4.319 mg of H₂O were obtained.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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