Suppose that segmentation method is used for memory management. Process A has these three values in its base registers: 32KB for code segment, 34KB for heap segment, and 28KB for stack segment. In the virtual memory of process A, the code segment takes the space from 0KB to 2KB, where its base register provides the relocation of 0KB. The heap segment takes the space from 4KB to 7KB, where its base register provides the relocation of 4KB. To fetch an instruction at virtual address 205, the kernel will use physical address ---------- (in decimal). To load a value to a register from the heap location with virtual address 4300, the kernel will use physical address ----------
Suppose that segmentation method is used for memory management. Process A has these three values in its base registers: 32KB for code segment, 34KB for heap segment, and 28KB for stack segment. In the virtual memory of process A, the code segment takes the space from 0KB to 2KB, where its base register provides the relocation of 0KB. The heap segment takes the space from 4KB to 7KB, where its base register provides the relocation of 4KB. To fetch an instruction at virtual address 205, the kernel will use physical address ---------- (in decimal). To load a value to a register from the heap location with virtual address 4300, the kernel will use physical address ----------
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Suppose that segmentation method is used for memory management. Process A has these three values in its base registers: 32KB for code segment, 34KB for heap segment, and 28KB for stack segment. In the virtual memory of process A, the code segment takes the space from 0KB to 2KB, where its base register provides the relocation of 0KB. The heap segment takes the space from 4KB to 7KB, where its base register provides the relocation of 4KB. To fetch an instruction at virtual address 205, the kernel will use physical address ---------- (in decimal). To load a value to a register from the heap location with virtual address 4300, the kernel will use physical address ----------
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