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- what is the advantage and disadvantage of lm78xxElectrical Engineering _ Power Electronics Notes: pls try to answer in less than 30 min.8.* A single phase bridge rectifier supplies a IkW washing machine induction motor drive. The smoothing capacitance is 6.8 mF and the smoothing inductance is 5 mH. At full load, the equivalent resistance of the induction motor is 24 2. The ac supply is 220 V (60Hz). (a) (b) (c) Estimate the ripple What is the capacitor 'de link' voltage under full load? What is the % voltage regulation no load to full load? ?
- sponse. Question 8 NPN BJT is considered as two diodes their anodes are connected together. True False Moving to another question will save this response. e to searchA Capacitor filter is used at the output across the load in order to minimize the ripple factor of the output voltage. The expressions of the average output voltage Vpc and the output AC component VAc are given below. If R = 1k2 and the single phase bridge rectifier supplied from a 120V - 50 Hz sinusoidal source, then the capacitor value that will maintain the amount of the output ripples to less than 4% would be equal to: VDC = Vm(4FRC – 1)/4ƒRC) VAC = Vm/(4/2ƒRC) Select one: O a. 63.39uF O b. 33.2uF O c. 93.39UF O d. 126.2uF TOSHIBAA full-wave rectifier operating from a 60HZ supply develops a peak rectifier voltage of 23V. Calculate the ripple factor for the voltage across the 223µF capacitor for a load current of 76mA. RL Idc 4/3fC Vr(rms) Lütfen birini seçin: a.3.56% b.11.6% c.9.46% d.7.37% e.4.89% ίφ00ορορο)
- Produce a working circuit with the Integrated Circuits shown in the image.8.15 MECT361 Mechatronics Components and Instrumentation 8.15. Using the Internet, look up the specifications for the National Semiconductor ( www.national.com ) ADC0800 8-bit A/D converter. Determine the maximum sam- pling rate and the method for performing the conversion. Also define each of the inputs and outputs. PLEASE GIVE ME THE REFRENCE I Will get zero if you didn't put the refrenceQuestion-3 Can you throw the emergency solution? I would appreciate it if you write legibly.
- The average (DC) value of a half-wave rectified voltage with a peak value of 200 V is: a. 63.7 V b. 127.3 V c. d. OV 141 V 2. Voltage regulation is determined by: a. load current b. Zener current and load current c. changes in load resistance and output voltage d. changes in no-load voltage and full-load voltage When a 60-Hz sinusoidal voltage is applied to the input of a full-wave rectifier, the output frequency is: a. 120 Hz b. 60 Hz c. 240 Hz d. 0 HzFor a circuit containing 1 SCR and a resistive load of 10 ohms and supply of 220V, 50HZ and the firing angle is adjusted at 60°. The d.c. output voltage is calculated as a. 71.2 V b. 70.2 V C. 742 V d. 74.2VSolve it fast fast plz