A Si sample at room temperature is doped wit Np = NA = 1*1014 / cm?. If n; = 1*1010 / cm?, and q = 1.6*10 19 C and Pn and p, are given at room temperature as shownin the given table:HnHpNA or Np (cm-3)1X 1014.. . .2(cm? / V-sec)135813574611352134546045945851X 1015. .2133245551X 1014 .....212981248116598644843741937833151X 1017.....801Then the conductivity of the sample is:

We need to find out the conductivity for given si sample. We know direct formula for conductivity of…

A Si sample at room temperature is doped wit No = Na = 1*1014 / cm?. If n; = 1*1010 / cm?, and q = 1.6*10 19 C and pn and u, are given at room temperature as shown in the given table: Hp NA or ND (cm-) IX 104 .. . .. 2 (cm? / V-sec) 461 1358 1357 1352 1345 460 459 458 455 5 IX 1015.. . .. 1332 5 1X 1016. . 2 1298 1248 1165 986 448 437 .... 419 5 378 1X 1017.. .. 801 331 Then the conductivity of the sample is:

A Si sample at room temperature is doped wit No = Na = 11014 / cm?. If n; = 11010 / cm?, and q = 1.6*10 19 C and pn and u, are given at room temperature as shown in the given table: Hp NA or ND (cm-) IX 104 .. . .. 2 (cm? / V-sec) 461 1358 1357 1352 1345 460 459 458 455 5 IX 1015.. . .. 1332 5 1X 1016. . 2 1298 1248 1165 986 448 437 .... 419 5 378 1X 1017.. .. 801 331 Then the conductivity of the sample is:

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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