Consider an p-type silicon for which the dopant concentration ND 1018/cm3 Find the electron and hole %3D concentrations at T= 350 K. electron = 1018 cm3 /em & holes= 2.25 x 102/em3 electron = 2.25 x 102/cm3 & holes= 2.25 x 104/cm3 electron = 17.22 x 104 /em3 & holes= 1018 cm3 18 cm3 %3D electron = 1018 em3 /cm° & holes= 10 %3D

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Consider an p-type silicon for which the dopant concentration Np = 1018/em3. Find the electron and hole
%3!
concentrations at T 350 K.
electron = 1018 cm3,
& holes= 2.25 x 102/cm3
ст
electron = 2.25 x 102/cm3 & holes= 2.25 x 104/cm3
104 /em3
electron = 1018/cm3 & holes= 10o18 cm3
electron = 17.22 x
& holes= 1018 cm3
%3D
Transcribed Image Text:Consider an p-type silicon for which the dopant concentration Np = 1018/em3. Find the electron and hole %3! concentrations at T 350 K. electron = 1018 cm3, & holes= 2.25 x 102/cm3 ст electron = 2.25 x 102/cm3 & holes= 2.25 x 104/cm3 104 /em3 electron = 1018/cm3 & holes= 10o18 cm3 electron = 17.22 x & holes= 1018 cm3 %3D
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