This problem demonstrates a possible (though rare) situation that can occur with group comparisons. Thegroups are sections and the dependent variable is an exam score.Section 1Section 2Section 35638.159.551.122.344.643616261.724.952.859.749.151.549.164.655.456.93954.665.446.348.34845.356Run a one-way ANOVA (fixed effect) with a = 0.05. Round the F-ratio to three decimal places and the p-value to four decimal places. Assume all population and ANOVA requirements are met.F =p =What is the conclusion from the ANOVA?O reject the null hypothesis: at least one of the group means is differentO fail to reject the null hypothesis: not enough evidence to suggest the group means are different

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Answered: Run a one-way ANOVA (fixed effect) with…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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With one-way ANOVAs, the null hypothesis is represented by which of the following? b0 the grand mean the total sum of squares the model sum of squares
For the Kruskal-Wallis ANOVA: Is there a statistical difference between the rankings of the core temperatures of the groups exposed to either a cold, neutral, or hot environment? (smaller number= coldest core temperature ranking, largest number= hottest core temperature ranking).” Ranks that are tied, get an average value of the two ranks. The Data is attached. Thank you.
Google Sheets can be used to find the critical value for an F distribution for a given significance level. For example, to find the critical value (the value above which you would reject the null hypothesis) for α=0.05 with dfbetween=4 and dfwithin=30, enter =FINV(0.05,4,30) Enter this into Google Sheets to confirm you obtain the value 2.69. You conduct a one-factor ANOVA with 8 groups and 10 subjects in each group (a balanced design). Use Google Sheets to find the critical values for α=0.1 and α=0.02 (report accurate to 3 decimal places).F0.1=F0.02=
An educational psychologist is examining response times to an on-screen stimulus. The researcher believes there might be a weak effect from age, but expects a more pronounced effect for different color contrasts. She decides to examine a black on white (B/W) combination compared to 2 alternatives: red on white (R/W) and yellow on blue (Y/B). Here is the data for response times (in milliseconds): Color Scheme B/W R/W Y/B 10 17 23 26 44 44 22 21 25 22 21 4 16-17 11 32 34 31 24 20 16 20 21 36 8 8 24 37 23 11 39 36 23 17 28 32 36 31 Age 18-19 19 15 45 15 35 36 13 47 23 16 19 31 24 30 25 16 40 16 27 25 42 23 28 35 20-21 21 18 42 27 19 39 39 28 27 18 26 38 Using MS Excel, conduct a 2-way ANOVA with a = 0.05. Fill in the summary table. The last column in the table below is read as, "Partial Eta-squared " and is a concept that was NOT covered in the lectures. Partial n2 is used when there is a chance the data is not independent (click here to read more if interested 2) Computing the values for…
P-values should be accurate to 4 decimal places and all other values accurate to 3 decimal places. Source S df MS F-ratio P-value Partial n? Age (A) 2 Color (B) Interaction (A × B) 4 Error 63 Provide the conclusions for this 2-way ANOVA. What is the conclusion regarding the main effect for age (A or rows): O There appears to be an effect due to age. O There is not enough evidence to reject the assumption that the marginal means across age groups are equal. What is the conclusion regarding the main effect for color (B or columns): There appears to be an effect due to color. There is not enough evidence to reject the assumption that the marginal means across color groups are equal. What is the conclusion regarding an interaction effect between age and color (A x B): There appears to be an interaction effect between age and color. There is not enough evidence to reject the assumption of a lack of an interaction.
Test the research hypothesis that there is a difference in weights between the two groups at the 0.05 significance level? Assume the equality of variance, adequate sample size, and normal distribution for both the groups to test the hypothesis. X1 = 200 X2 = 198 n1 = 17 n2 = 17 s1 = 2.45 s2 = 2.35 Please show all the necessary steps of hypothesis testing to answer this question.
Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use a significance level of 0.05 to test the claim. One-way ANOVA: Source DF SS MS F P Size 3 13.500 4.500 5.17 0.011 Error 16 13.925 0.870 Total 19 27.425 can you show how you worked it out please
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You wish to test the following daim (Ha) at a significance level of a = 0.05. Ho:P1 P2 You obtain a sample from the first population with 422 successes and 126 failures. You obtain a sample from the second population with 385 successes and 176 failures. critical value = [three decimal accuracy] test statistic = [three decimal accuracy]
The Barbadian Farming Association has been supplied with a new feed for cows which has been touted to maintain the body weight of the animals over time. The body weights of 20 cows are collected at interval of 4 weeks since birth to 20 weeks of age and are given in table (image file) below: A. Use the data above to conduct a One-Way Repeated Measures ANOVA. What would you conclude from your hypothesis test? Clearly outline all steps. B. Interpretand report on the relevant information presented in the following tables: Mauchly'stest Testfor normality Pairwisecomparison C. Would an ANCOVA test be more appropriate for this research? D. What is the JASP output of all the statistical analyses performed as well as the file that was produced should be provided.
You are conducting a study to see if the proportion of men over 50 who regularly have their prostate examined is significantly different from 0.45. You use a significance level of α=0.002. H0:p=0.45 H1:p≠0.45You obtain a sample of size n=196 in which there are 81 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is different from 0.45. There is not sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their…
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