A body mass index of more than 25 is considered unhealthful. The technology output given is from 50 randomly and independently selected people from a health agency's study. Test the hypothesis that the mean BMI is morethan 25 using a significance level of 0.05. Assume that conditions are met.One-Sample TTest of u = 25 vs > 25MeanStDevSE MeanTP5027.7076.1910.8763.090.002Determine the null and alternative hypotheses. Choose the correct answer below.O A. H,: u= 25H3: u> 25O C. H,: µ> 25H3: us 25O B. H,: u= 25H3 u<25O D. Ho: H< 25O E. H,: u#25OF. Ho: H= 25H3: u2 25H3: u = 25H3: u# 25The test statistic is(Type an integer or decimal rounded to two decimal places as needed.)The p-value is(Type an integer or decimal rounded to three decimal places as needed.)Interpret the results of the test.Since the p-value isthe significance level,Ho. There isevidence to conclude that the mean BMI is more than 25 using a significance level of 0.05.

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Answered: A body mass index of more than 25 is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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production of urc acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma over the period of thirteen months The mean concentrations was X = 5.33 mg/dI. The distribution of uric acid in healthy adult males can be assumed to be normal, with a =1.75 mg/di. Find the sample size necessary for a 95% confidence level with maximal margin of error E - 414 for the mean concentration
A random sample of 5 students IQ scores have a mean score of 107.04 and a standard deviation of 6.08.Is there sufficient evidence to support the claim that this sample of students are greater than the average IQ of 107? Use a 0.005 significance level. The test statistic is:
The average retirement age in America is 66 years old. Do small business owners retire at an older average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 60, 60, 72, 76, 71, 77, 77, 64, 68, 61, 68, 72 What can be concluded at the the αα = 0.05 level of significance level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer > ≠ < = H1:H1: ? μ p Select an answer < ≠ = > The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer accept reject fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the…
What type of hypothesis test should be performed?
Manually construct a graph portraying the decision criterion for the specified hypothesis test. Upload a clear, legible photo of your work (which adheres to the File Upload Guidelines for Photos). A hypothesis test for a population mean is conducted. The hypotheses are: Ho: μ = Ho H₂: μ ‡ Ho Ha: μ < Ho The significance level is 0.10 and the critical value is z=-1.28. Sketch a normal curve displaying the decision criterion. This curve will represent the normal curve for the test statistic under the assumption that the null hypothesis is true. On your graph indicate the area in the tail, the critical value, the rejection region, and the nonrejection region. Upload Choose a File
Suppose the mean height of women age 20 years or older in a certain country is 62.2 inches. One hundred randomly selected women in a certain city had a mean height of 61.7 inches. At the 1% significance level, do the data provide sufficient evidence to conclude that the mean height of women in the city differs from the national mean? Assume that the population standard deviation of the heights of women in the city is 3.9 inches. Set up the hypotheses for the one-mean z-test. H0: μ (≠, >, <, =) ________ppmHa: μ (≠, >, <, =) _________ppm Compute the value of the test statistic.z=__________(Round to two decimal places as needed.) Determine the critical value(s). Select the correct choice below and fill in the answer box within your choice. (Round to two decimal places as needed.) A. The critical value is zα=____________ B. The critical values are ±zα/2=±____________ C. The critical value is −zα=___________
A poll of 100 randomly selected car owners revealed that the mean length of time that they plan to keep their cars is 6.75 years and standard deviation is 3.60 years. Test the claim that the mean length of time for all car owners to keep their cars is less than 7.50 years. Use a 0.05 significance level.
poll used a sample of 100 randomly selected car owners. Within the sample, the mean time of ownership for a single car was 7.18 years with a standard deviation of 3.37 years. Test the claim by the owner of a large dealership that the mean time of ownership for all cars is less than 7.5 years. Use a 0.05 significance level. Find the Z score and P value and if left-tailed or right-tailed. Also to reject or not too.
A researcher is studying hospitals cleanliness comparing carpeted rooms with uncarpted rooms. This researcher would like to determine if the mean number of airborne bacteria (per cubic foot) in carpeted rooms differs from the mean amount of airborne bacteria in uncarpeted rooms. To test thus, carpeted and uncarpeted hospitals rooms were randomely selected. Then air from the room was pumped over a petri dish and the number of bacteria of the patri dish was recorded. Since both samples are small (less than 30), you may assume that number of bacteria per petri dish is normally distributed. Using significant level =.05, use the unequal varance t-test for means to determine if the mean number of airborne bacteria in carpeted rooms differs from the mean number of airborne bacteria in uncarpeted rooms. Follow all steps and remember that you must assign population 1 and population 2 before you set up your Ho and Ha.
Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women
The amount of water consumed each week by Bronx residences is normally distributed. The population mean of water consumption is 120.3 gallons with a standard deviation of 10.0 gallons. Test the claim at the 0.10 significance level that the average amount of water consumed is not 125 gallons with a sample size of 100 residences. Do you retain or reject the null hypothesis?
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