Write your conclusion.The p-value isV the significance level,the null hypothesis. The study indicates that speed Two students collected data on random baseball player run-times. Players were required to run 50 yards and were timed in seconds (pitchers did not have to run). Assume that the distribution of each population (outfielders,infielders, catchers) is close enough to Normal to satisfy the Normal condition for using ANOVA. Test the hypothesis that different positions have different mean run-times, using a significance level of 0.05. Do not do post-hoc tests.E Click the icon to view the data.Student dataWrite the null and alternative hypotheses.Ho:V or thereV between field position and speed.OutfieldersInfieldersCatchers6.677.677.93HV or thereV between field position and speed.6.797.217.78Which of the conditions for ANOVA can be assumed to be satisfied based on the given information or can be shown to be satisfied? Select all that apply.7.126.357.887.467.167.59O A. random and independent samples7.037.078.776.347.147.43O B. Normality7.156.85O C. equal variance7.077.05O D. independent groups7.438.586.936.32The test statistic is|7.027.09(Round to two decimal places as needed.)7.33The p-value is(Round to three decimal places as needed.)Write your conclusion.PrintDono

Given that two students collected data on random baseball player run times. Using the data we have…

Answered: Two students collected data on random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A manufacturing company wants to see if there is a significant difference in three types of plastic for a new product. They randomly sample prices for each of the three types of plastic and run an ANOVA. Use α = 0.05 to see if there is a statistically significant difference in the mean prices. Part of the computer output is shown below, fill in the missing information. Use alpha= 0.01. a. Compute the test statistic. Fill out the entire ANOVA table. Round answers to at least 4 decimal places. Sample Mean Sample Size High-Density Polythene 38.5673 11 Low-Density Polythene 38.0473 15 Polyethylene Terephthalate 35.8375 8 Source S.S. df M.S. F Treatment Incorrect Correct Incorrect Incorrect Error Incorrect Correct 6.69797 Total 245.471038 Correct b. What is the critical value? Incorrect c. What is the correct decision?
A study of seat belt yielded the randomly selected sample data summarized in the accompanying table. Use a 0.05 significance level to test the claim that the amount of smoking is independent of seat belt use. A plausible theory is that people who smoke dy are less concerned about their health and safety and are therefore less inclined to wear seat belts. Is this theory supported by the sample data? 5 sic Click the icon to view the data table. use. ..... Hа: Heavy Determine the test More info izlet. y of X-(Round to claim Number of Cigarettes Smoked per Day 15-34 Determine the P-v 1-14 35 and over le wh Wear Seat Belts 190 13 36 10 P-Value = (Rou Don't Wear Seat Belts 152 13 45 ww.nur y is that people ry supported by Use a 0.05 signific who smoke are les the sample data? nour seat Done theory is not zed in t Print O A. There is nd supported S Top eat belt. The O B. There is no theory is supportou Dy ao vampIG Gutu. O C. There is sufficient evidence to reject the claim that heavy smokers…
A public bus company official claims that the mean waiting time for Bus # 14 during peak hours is approximately 10 minutes. Karen took Bus # 14 during peak hours on 36 different occasions. Her mean waiting time was 8.7 minutes. Assume that the population standard deviation o of 2.9 minutes is known. At the 0.01 significance level, test if the mean of all the peak hours waiting time for Bus # 14 is significantly different from 10 minutes.
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A marketing research consultant interested in determining the proportion of customers who use online dating services. A random sample of 2001 people were asked and the count revealed that 15% used online dating services. Data 10 Samples Generate 100 Samples Generate 1000 Samples Reset Plot portion- ht Tail samples - do00 mean- o, 150 std. error=0,008O 0.025 0.950 0.025 0.130 o135 o50 0.16 0.140 0.145 0.155 0.160 0.170 0.175 0.15 0.134 0.166 Compute a 95% confidence interval for the true proportion of people who use online dating. 95% Confidence interval What is the numerical value of the margin of error? If the researcher is using a confidence level of 95% what percent of confidence intervals would not capture the true parameter?
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
Longevities of Archbishops and Monarchs 16 Archbishops 16 15 15 16 17 1 18 18 10 13 13 11 13 11 11 17 18 10 18 12 19 17 Monarchs 14 18 14 13 19 16 21 14 16 17 15 16
Perform a left tail test to test whether Machine-2 has less variability. Use a significance level of 0.01. What is the conclusion of the test results?
Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm Left arm 151 136 120 134 134 181 174 180 156 138 In this example, Ha is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Hd = 0 O B. Ho: Hd 0 O C. Ho: Hd = 0 O D. Ho: Hd 0 H1: Ha>0
Do men score lower on average compared to women on their statistics finals? Final exam scores of twelve randomly selected male statistics students and twelve randomly selected female statistics students are shown below. Male: 89 94 88 64 57 58 62 83 82 88 57 78 Female: 81 80 65 66 97 92 70 94 82 90 65 93 Assume both follow a Normal distribution. What can be concluded at the the a = 0.10 level of significance level of significance? For this study, we should use Select an answer a. The null and alternative hypotheses would be: Ho: Select an answer Select an answer Select an answer v (please enter a decimal) H1: Select an answer v Select an answer v Select an answer ♥ (Please enter a decimal) b. The test statistic ? v = (please show your answer to 3 decimal places.) c. The p-value = d. The p-value is ? v a e. Based on this, we should Select an answer v the null hypothesis. f. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) O The results are…

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